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Lunna [17]
3 years ago
10

Property of equality used to solve subtractior equations

Mathematics
1 answer:
Margarita [4]3 years ago
4 0
Two equations that have the same solution are called equivalent equations e.g. 5 +3 = 2 + 6. And this as we learned in a previous section is shown by the equality sign =. An inverse operation are two operations that undo each other e.g. addition and subtraction or multiplication and division. You can perform the same inverse operation on each side of an equivalent equation without changing the equality
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I need help with #6 please.
Juliette [100K]

9514 1404 393

Answer:

  6. (A, B, C) ≈ (112.4°, 29.5°, 38.0°)

  7. (a, b, C) ≈ (180.5, 238.5, 145°)

Step-by-step explanation:

My "work" is to make use of a triangle solver calculator. The results are attached. Triangle solvers are available for phone or tablet and on web sites. Many graphing calculators have triangle solvers built in.

__

We suppose you're to make use of the Law of Sines and the Law of Cosines, as applicable.

6. When 3 sides are given, the Law of Cosines can be used to find the angles. For example, angle A can be found from ...

  A = arccos((b² +c² -a²)/(2bc))

  A = arccos((8² +10² -15²)/(2·8·10)) = arccos(-61/160) = 112.4°

The other angles can be found by permuting the variables appropriately.

  B = arccos((225 +100 -64)/(2·15·10) = arccos(261/300) ≈ 29.5°

The third angle can be found as the supplement to the other two.

  C = 180° -112.411° -29.541° = 38.048° ≈ 38.0°

The angles (A, B, C) are about (112.4°, 29.5°, 38.0°).

__

7. When insufficient information is given for the Law of Cosines, the Law of Sines can be useful. It tells us side lengths are proportional to the sine of the opposite angle. With two angles, we can find the third, and with any side length, we can then find the other side lengths.

  C = 180° -A -B = 145°

  a = c(sin(A)/sin(C)) = 400·sin(15°)/sin(145°) ≈ 180.49

  b = c(sin(B)/sin(C)) = 400·sin(20°)/sin(145°) ≈ 238.52

The measures (a, b, C) are about (180.5, 238.5, 145°).

7 0
3 years ago
a student correctly answered 80% of the 2o questions on the test How many questions did the student answer correctly
NeX [460]
16 questions right is the answer




4 0
3 years ago
Read 2 more answers
Which answer explains the correct way to move the decimal to find the quotient of 23.8 × 100?
natima [27]
The correct way to move the decimal to find the quotient is b. two places to the right.

This is because 100 has two zeroes in it, so you know that you have to move the decimal either two places to the right or two places to the left.  

100 is a positive number, and when multiplied by a positive number with a decimal, it makes an even larger number.  So, you would move 23.8 decimal place two places to the right.
6 0
3 years ago
Divide 7/15 by 3/5. <br> A. 75/21<br> B. 7/9<br> C. 7/25<br> D. 21/75
Digiron [165]
In this question there is nothing complicated. Only thing is to know the way fractions can be divided. Once that is known the problem would be one of the easiest to solve. Now let us get back to the problem and look at all the information's that are given in the question.
Divide 7/15 by 3/5 = (7/15)/(3/5)
                              = (7 * 5)/(15 * 3)
                               = (35/45)
Dividing the numerator and the denominator by 5 for simplifying purpose, we get
                               = 7/9
So from the above deduction we can easily conclude that 7/9 is the correct answer and option "B" is the correct option among all the options given in the question.
5 0
3 years ago
Read 2 more answers
X^2-x+12 solve using the quadratic formula
devlian [24]

The quadratic formula is x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}.

From the problem, a is 1, b is -1, and c is 12. Plugging in these values gives:

x=\frac{-(-1(-1)\pm\sqrt{(-1)^2-4(1)(12)} }{2(1)}

Because there is a square root of a negative number, there is no solution.

4 0
3 years ago
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