Considering the perimeter of the rectangle, we have that the length is of 9 inches and the width is of 55 inches.
<h3>What is the perimeter of a rectangle?</h3>
The perimeter of a rectangle of length l and width w is given as follows:
P = 2(l + w).
The length is an odd integer and the width is <u>5 times the next consecutive odd integer,</u> hence:
l = x, w = 5(x + 2).
The perimeter is of 128 inches, hence:
128 = 2l + 2w
128 = 2x + 10(x + 2)
128 = 2x + 10x + 20
12x = 108
x = 9.
Hence the length is of 9 inches and the width is of 55 inches.
More can be learned about the perimeter of a rectangle at brainly.com/question/10489198
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I don't understand what you are trying to say
The answer is c.
(a)
x * 2 = y
2 * 2 = 4
3 * 2 = 6
4 * 2 = 8 not 9
(b)
unknown formula
(c)
x * 3 = y
4 * 3 = 12
5 * 3 = 15
6 * 3 = 18
(d)
x * 4
1 * 4 = 4
2 * 4 = 8
3 * 3 = 9 not 15