By applying section formula we got that y-coordinate of the point that divides the directed line segment from J to K into a ratio of 5:1 is $\frac{5y_2+y_1}{6}$

<h3>What is section formula ?</h3>

Let point P(x,y) cuts line joining point $A(x_1,y_1)$ and $B(x_2,y_2)$ in $m_1:m_2$ then coordinate of point P is equal to $(\frac{m_1x_2+m_2x_1}{m_1+m_2}, \frac{m_1y_2+m_2y_1}{m_1+m_2})$

Here given that point divides line segment from J to K into a ratio 5:1

$m_1=5\\\\m_2=1$

Now we have to fin y coordinate of point that divides the directed line segment from J to K into a ratio of 5:1

We can calculated y coordinate by applying section formula as :

$\frac{5y_2+1y_1}{5+1}\\\\\frac{5y_2+y_1}{6}$

By applying section formula we got that y-coordinate of the point that divides the directed line segment from J to K into a ratio of 5:1 is $\frac{5y_2+y_1}{6}$

To learn more about section formula visit:brainly.com/question/26433769

4 0

3 years ago

Solve the following equation. Then place the correct number in the box provided. x/9 = 1

BARSIC [14]

First, we need to isolate the variable x.

To isolate x, we simply need to multiply both sides by 9, which would result in x = 9

3 0

3 years ago

Read 2 more answers

7u=48 fill it in , one -step equations :integers

marissa [1.9K]