3 years ago

This is really hard... can anyone help..? Please no wrong answers

Mathematics

1 answer:

kifflom [539]3 years ago

7 0

Answer:

Step-by-step explanation:

I believe I answered a similar question, the reasoning behind it is the same.

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Step-by-step explanation:

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4 years ago

In Exercise, find the derivative of the function.<br> y = 3ex - xex

nevsk [136]

Answer:

the question is incomplete, the complete question is "find the derivative of the function $y=3e^{x}-xe^{x}$ "

answer: $\frac{dy}{dx}=(2-x)e^{x}$ .

Step-by-step explanation:

From the equation, $y=3e^{x}-xe^{x}$ , we approach the question using the differentiation of a product and differentiation of a sum simultaneously,

the differentiation of a sum is express as

f(x)=u(x)+v(x)+.....w(x) then

$\frac{df(x)}{dx}=\frac{du(x)}{dx}+\frac{dv(x)}{dx}+...\frac{dw(x)}{dx}.\\$

For the differentiation of a product we have

f(x)=u(x)v(x), then

$\frac{df(x)}{dx}=\frac{dv(x)}{dx}u(x)+\frac{du(x)}{dx}v(x)$

hence if we go by the formula we arrive at

for $y=3e^{x}$

let u(x)=3 hence du/dx=0 and

$v(x)=e^{x}$ and $\frac{dv(x)}{dx}=e^{x}$

hence $\frac{dy}{dx}=3e^{x}+0e^{x}\\\frac{dy}{dx}=3e^{x}---equation 1\\$

Also for $y=-xe^{x}\\\frac{dy}{dx}=-e^{x}-xe^{x}---equation 2$ .

if we add equation 1 and equation 2 we arrive at

$\frac{dy}{dx}=3e^{x}-e^{x}-xe^{x}\\\frac{dy}{dx}=(3-1-x)e^{x}\\\frac{dy}{dx}=(2-x)e^{x}$ .

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What is the result of -7+10-(-3)?

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Answer:6

Step-by-step explanation:

-7+10-(-3)

Using BODMAS

-7+10+3

3+3=6

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