Polynomials are equations that uses variables and several terms
The polynomial in standard form is f(x) = x^2 - x -20
<h3>How to determine the polynomial</h3>
The polynomial has 2 zeros.
So, the form of the polynomial is:
f(x) = a(x - x1)(x - x2)
The zeros of the polynomial are 5 and -4.
So, the equation becomes
f(x) = a(x - 5)(x + 4)
The value of a = 1.
So, we have;
f(x) = 1(x - 5)(x + 4)
This gives
f(x) = (x - 5)(x + 4)
Expand
f(x) = x^2 - x -20
Hence, the polynomial in standard form is f(x) = x^2 - x -20
Read more about polynomials at:
brainly.com/question/2833285
<h2>Recurring decimals such as 0.26262626…, all integers and all finite decimals, such as 0.241, are also rational numbers. Alternatively, an irrational number is any number that is not rational. ... For example, the square root of 2 is an irrational number because it cannot be written as a ratio of two integers.</h2><h2>Worked Examples
</h2><h2>1 - recognize Surds
</h2><h2>A surd is a square root which cannot be reduced to a whole number.
</h2><h2>
</h2><h2>For example,
</h2><h2>
</h2><h2>4–√=2
</h2><h2>is not a surd, because the answer is a whole number.
</h2><h2>
</h2><h2>Alternatively
</h2><h2>
</h2><h2>5–√
</h2><h2>is a surd because the answer is not a whole number.
</h2><h2>
</h2><h2>You could use a calculator to find that
</h2><h2>
</h2><h2>5–√=2.236067977...
</h2><h2>but instead of this we often leave our answers in the square root form, as a surd.
</h2><h2>
</h2><h2>2 - Simplifying Surds
</h2><h2>During your exam, you will be asked to simplify expressions which include surds. In order to correctly simplify surds, you must adhere to the following principles:
</h2><h2>
</h2><h2>ab−−√=a−−√∗b√
</h2><h2>a−−√∗a−−√=a
</h2><h2>Example
</h2><h2>(a) - Simplify
</h2><h2>
</h2><h2>27−−√
</h2><h2>Solution
</h2><h2>(a) - The surd √27 can be written as:
</h2><h2>
</h2><h2>27−−√=9–√∗3–√
</h2><h2>9–√=3
</h2><h2>Therefore,
</h2><h2>
</h2><h2>27−−√=33–√
</h2><h2>Example
</h2><h2>(b) - Simplify
</h2><h2>
</h2><h2>12−−√3–√
</h2><h2>Solution
</h2><h2>(b) -
</h2><h2>
</h2><h2>12−−√3–√=12−−√∗3–√=(12∗3)−−−−−−√=36−−√
</h2><h2>36−−√=6
</h2><h2>Therefore,
</h2><h2>
</h2><h2>12−−√3–√=6
</h2><h2>Example
</h2><h2>(c) - Simplify
</h2><h2>
</h2><h2>45−−√5–√
</h2><h2>Solution
</h2><h2>(c) -
</h2><h2>
</h2><h2>45−−√5–√=45/5−−−−√=9–√=3
</h2><h2>Therefore,
</h2><h2>
</h2><h2>45−−√5–√=3</h2>
60 because all the negatives would cancel out so all you have to do is multiply the numbers
Answer:
Step-by-step explanation:
A)
<u>Each edge of the greater cube has:</u>
- 1 : 1/6 = 6 times the small cube
<u>Number of small cubes:</u>
B)
The volume of the bigger cube is 1 in³
<u>The volume of each small cube is:</u>
