A parallel line has the same slope as the original line. So in this case the slope of the line is also 3/4. Now how do we know if it intersects the point? We need to adjust the y intercept.
Currently, we know the equation of the line is y= 3/4 x + b, where b is the thing we are looking for. We also have a point, which supplies the x and y. Plug that in and solve for b
-2 = (3/4)*(12) + b
You'll get b= -11
So the equation of the parallel line intersecting the point given is y= 3/4x -11.
I am assuming that the slope is 3/4 based on the way you formatted the original equation, but it's the same steps if the slope is different.
Answer:
-2 < x < 2
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer:
25
Step-by-step explanation:
If it gives a result of -4 then our equation will have .... = -4
If we subtract 9 from the quotient of a number and 5 we have x/5 - 9
Our equation is:
x/5 - 9 = -4 add 9 to both sides
x/5 = -4 + 9
x/5 = 5 multiply both sides by 5
x = 5(5)
x = 25
Check: 25/5 - 9 = 5-9 = -4
Answer checks as correct from information given
we have
we know that
The radicand must be greater than or equal to zero
so
the domain is is the interval--------> [-2.25,∞)
therefore
<u>the answer is</u>
