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luda_lava [24]
3 years ago
11

Buoyancy All soda cans contain the same

Physics
1 answer:
Tems11 [23]3 years ago
7 0

Answer:

The correct answer is - Regular soda can would sink and diet soda can will float.

Explanation:

The correct answer is - Regular soda can would sink and diet soda can will float.

Reason - As diet soda cans contains artificial sweetener so, the weight of the diet soda can is less the the eight of the regular soda so. Due to this reason , diet soda can will float and another one sinks in water.

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For a wavelength of 420 nm, a diffraction grating produces a bright fringe at an angle of 24°. For an unknown wavelength, the sa
Inessa [10]

Answer:

649.8420 nm

Explanation:

We have given \Theta _1=24^{\circ} \ and\ \Theta _2=39^{\circ}

\lambda _1=420\ nm we have to find unknown wavelength that is \lambda _2

The condition for constructive interference is dsin\Theta =n\lambda

Where d is distance between slits \Theta is angle of emergence and n is order of maxima

Using constructive interference equation

dsin\Theta _1=n\lambda _1 ---------eqn 1

dsin\Theta _2=n\lambda _2---------eqn 2

On dividing eqn 1 by eqn 2

\frac{\lambda _1}{\lambda _2}=\frac{sin\Theta _1}{sin\Theta _2}

\frac{420}{\lambda _2}=\frac{sin24^{\circ}}{sin39^{\circ}}

\lambda _2=649.8420\ nm  

7 0
3 years ago
Janice has just measured the density of an object. Which value is possible? (Density: D = m)
stira [4]

Explanation:

The density of an object can be calculated using the formula as follows :

d=\dfrac{m}{V}

Here,

m is mass of the object and V is its volume

The mass of an object can b measured in grams and its volume in cubic cm. So, the density of object is measured in g/cm³. Hence, out of given options the possible value of density of an object is 6 g/cm³.

8 0
4 years ago
Read 2 more answers
Una sustancia radioactiva, cuya temperatura es inconstante, aumenta su temperatura en 30ºF, luego disminuye e 40ºC, luego aument
irakobra [83]

Answer:

What the heck

Explanation:

6 0
4 years ago
A 1.10 kg box slides down a rough incline plane from a height h of 1.75 m. The box had a speed of 2.99 m/s at the top and a spee
madam [21]

Answer:

20.18 J

Explanation:

We are given that

Mass of bx=m=1.1 kg

Height=h=1.75 m

Initial speed of box=u=2.99 m/s

Final speed,v=2.56 m/s

We have to find the mechanical energy lost due to friction.

Energy at top=K.E+P.E=\frac{1}{2}mu^2+mgh=\frac{1}{2}(1.1)(2.99)^2+1.1\times 9.8\times 1.75=23.78 J

Where g=9.8 m/s^2

At bottom,h'=0

Energy at bottom=\frac{1}{2}mv^2+mgh'=\frac{1}{2}(1.1)(2.56)^2+0=3.6 J

Energy lost=Energy(Top)-Energy(bottom)=23.78-3.6=20.18 J

5 0
3 years ago
13. Now we will examine the electric field of a dipole. The magnitude and direction of the electric field depends on the distanc
Gennadij [26K]

This question is incomplete, the complete question is;

Now we will examine the electric field of a dipole. The magnitude and direction of the electric field depends on the distance and the direction. We will investigate in detail just two directions. With charges available in the simulation (all the charges are either positive or negative 1 nC increments).

how do you create a dipole with dipole moment 1 x 10-9 Cm with a direction for the dipole moment pointing to the right. Make a table below that shows the amounts of  charge and the distance between the charges. There are many correct answers

Answer:

Given the data in question;

Dipole moment P = 1 × 10⁻⁹ C.m

now dipole pointing to the right;

               P→

_{-\theta } (-) ---------------->(+) _{+\theta }

               d

so let distance between the dipoles be d

∴ P = d\Theta

Let \Theta_{1} = 1 nC

so

P = d\Theta

1 × 10⁻⁹ =  1 × 10⁻⁹  × d

d = (1 × 10⁻⁹) / (1 × 10⁻⁹)

d = 1 m

Also Let \Theta_{2} = 2 nC

so

P = d\Theta

1 × 10⁻⁹ =  2 × 10⁻⁹  × d

d = (1 × 10⁻⁹) / (2 × 10⁻⁹)  

d = 0.5 m

Also Let \Theta_{3} = 3 nC

so

P = d\Theta

1 × 10⁻⁹ =  3 × 10⁻⁹  × d

d = (1 × 10⁻⁹) / (3 × 10⁻⁹)

d = 0.33 m

such that;

charge                 distance

1 nC                        1.00 m      

2 nC                       0.50 m

3 nc                        0.33 m

4 nC                       0.25 m

5 nC                       0.20 m      

5 0
3 years ago
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