Answer:
v= 335 m/s
2∆t= 0.75 s
∆x= v.∆t → ∆x= 335×½×0.75 = 125.625 m
GPE I am assuming is gravitational potential energy. I'll denote it as U for simplicity.
U = mgy
U = (70kg)(9.81m/s^2)(1m) = 686.7J
U = 686.7J
Hope this helps!
The answer to this question is b
Explanation :
It is given that :
The initial velocity of the car is 10 m/s.
Juliette sets the acceleration to zero.
We know that, acceleration
\
where,
u is the initial velocity and v is the final velocity.
So, final velocity will become 10 m/s.
Hence, the car will move with the constant velocity i.e. 10 m/s.
So, Shakina described that the car will move with the constant velocity of 10 m/s as acceleration is zero.