1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dangina [55]
3 years ago
15

A 1.10 kg box slides down a rough incline plane from a height h of 1.75 m. The box had a speed of 2.99 m/s at the top and a spee

d of 2.56 m/s at the bottom. Calculate the mechanical energy lost due to friction (as heat, etc.).
Physics
1 answer:
madam [21]3 years ago
5 0

Answer:

20.18 J

Explanation:

We are given that

Mass of bx=m=1.1 kg

Height=h=1.75 m

Initial speed of box=u=2.99 m/s

Final speed,v=2.56 m/s

We have to find the mechanical energy lost due to friction.

Energy at top=K.E+P.E=\frac{1}{2}mu^2+mgh=\frac{1}{2}(1.1)(2.99)^2+1.1\times 9.8\times 1.75=23.78 J

Where g=9.8 m/s^2

At bottom,h'=0

Energy at bottom=\frac{1}{2}mv^2+mgh'=\frac{1}{2}(1.1)(2.56)^2+0=3.6 J

Energy lost=Energy(Top)-Energy(bottom)=23.78-3.6=20.18 J

You might be interested in
Please help urgent
artcher [175]
I think it will move down because this force it is 4N more than all force
8 0
3 years ago
How could the movement of tectonic plates create another supercontinent like Pangaea
Yuki888 [10]
Since the continents are moving ever so slightly over the years, in couple million years they could all connect again like Pangaea.
3 0
3 years ago
1. Find the magnitude of the gravitational force (in N) between a planet with mass 8.00 ✕ 1024 kg and its moon, with mass 2.75 ✕
MrRissso [65]

Answer:

1.358 10e8 have good day please mark brainliest

8 0
3 years ago
A projectile thrown up ward moves in its parabolic path at what point..
Romashka [77]

Answer:

please give me brainlist and follow

Explanation:

As the projectile moves upward, its vertical component of velocity decreases due to gravity. While the horizontal component remains the same as there is no acceleration in the horizontal direction. At maximum height vertical component of velocity is zero.

4 0
3 years ago
Read 2 more answers
An object moves with a positive acceleration. Could the object be moving with increasing speed, decreasing speed or constant spe
Masja [62]

Answer:

Increasing speed.

Explanation:

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

In this scenario, an object moves with a positive acceleration. Thus, the object is moving with an increasing speed and as such it has acceleration in the same direction as its velocity with respect to time.

3 0
3 years ago
Other questions:
  • State the periodic law
    6·1 answer
  • What is a fossil lineage?
    13·2 answers
  • What is the mass of an atom that has 11 protons, 16 neutrons, and 11 electrons? 11 22 27 38
    13·1 answer
  • I need help on 7 &8
    12·1 answer
  • An optical fiber uses one glass clad with another glass. What is the critical angle? (Assume the glass in the fiber has an index
    5·1 answer
  • Answer these, and tell me HOW you got to the answer.
    13·1 answer
  • if a sine wave representing ac voltage has an effective value of 70 vac what would be the waves peak value​
    15·1 answer
  • The cornea of the eye has a radius of curvature of approximately 0.40 cm , and the aqueous humor behind it has an index of refra
    7·1 answer
  • What is -0.000000698 in scientific notation
    7·1 answer
  • A book on a 2-meter high shelf has a mass of 0.4 kg. What is its potential energy?
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!