Find two consecutive positive integers such that the square of the larger integer is nineteen more than nine times the smaller i
1 answer:
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Answer:
other x values are -5,-4
Step-by-step explanation:
f(x)=0 for x=−6
Apply synthetic division to get the quotient . using that we find other two values of x
-6 1 15 74 120
0 -6 - 54 -120
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1 9 20 0
the quotient is
now factor the left hand side, product is 20 and sum is 9
So other x values are -5,-4