Find two consecutive positive integers such that the square of the larger integer is nineteen more than nine times the smaller i
1 answer:
You might be interested in
Answer:
x = 4.712145
Step-by-step explanation:
Given a=20 and b=28,
c = 4√74 = 34.409301068171
∠α = 35.538° = 35°32'16" = 0.62025 rad
∠β = 54.462° = 54°27'44" = 0.95055 rad
Area = 280
Perimeter = 82.409301068171
<h2><u>_____________________________________</u></h2>Let's solve your equation step-by-step.
9x−8=34.409301
Step 1: Add 8 to both sides.
9x−8+8=34.409301+8
9x=42.409301
Step 2: Divide both sides by 9.
x=4.712145
<h2>Answer:</h2><h2>x=4.712145</h2>