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astraxan [27]
3 years ago
15

What is the value of x?

Mathematics
2 answers:
Alex_Xolod [135]3 years ago
8 0
X=7 because it’s the closest
musickatia [10]3 years ago
6 0
X = 7. Because both lines equal the same so it has to equal 75
11 x 7 = 77
77-2 = 75
X = 7
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A piece of paper is to display ~128~ 128 space, 128, space square inches of text. If there are to be one-inch margins on both si
Grace [21]

Answer:

The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

Area = 128

Let the dimension of the paper be x and y;

Such that:

Length = x

Width = y

So:

Area = x * y

Substitute 128 for Area

128 = x * y

Make x the subject

x = \frac{128}{y}

When 1 inch margin is at top and bottom

The length becomes:

Length = x + 1 + 1

Length = x + 2

When 2 inch margin is at both sides

The width becomes:

Width = y + 2 + 2

Width = y + 4

The New Area (A) is then calculated as:

A = (x + 2) * (y + 4)

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A = (\frac{128}{y} + 2) * (y + 4)

Open Brackets

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Collect Like Terms

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To calculate the smallest possible value of y, we have to apply calculus.

Different A with respect to y

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Set

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0 = -512y^{-2} + 2

Collect Like Terms

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Multiply through by y^2

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512 = 2y^2

Divide through by 2

256=y^2

Take square roots of both sides

\sqrt{256=y^2

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y = 16

Recall that:

x = \frac{128}{y}

x = \frac{128}{16}

x = 8

Recall that the new dimensions are:

Length = x + 2

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So:

Length = 8 + 2

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To double-check;

Differentiate A'

A' = -512y^{-2} + 2

A" = -2 * -512y^{-3}

A" = 1024y^{-3}

A" = \frac{1024}{y^3}

The above value is:

A" = \frac{1024}{y^3} > 0

This means that the calculated values are at minimum.

<em>Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches</em>

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Step-by-step explanation:

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