Answer:
man did you ever find out the answer bc I'm dying I cannot fail this test-
Answer:
Step-by-step explanation:
8/25 38 0.41
We solve the equation, ( a + a + 1 )^2 = 112 + a^2 + ( a + 1 )^2;
Then, ( 2a + 1 )^2 = 112 + a^2 + a^2 + 2a +1;
4a^2 + 4a + 1 = 113 + 2a^2 + 2a;
Finally, 2a^2 + 2a - 112 = 0;
a^2 + a - 56 = 0;
We use <span>Quadratic Formula for this Quadratic Equation;
The solutions are a1 = 7 and a2 = -8;
But a is a natural number; so, a = 7;
The natural consecutive numbers are 7 and 8.</span>
Out of the total 60 students 18 take Algebra 1 and 20 take Algebra II. 10 take both. So out of the 18 taking algebra 10 are taking Algebra II. If we don't count that 10 because they are already counted in Algebra II count. So 28 students are taking either course. Therefore 60-28 = 32 students who are not taking either of these courses
Answer:
This person have a 29 % probability to receive a speeding ticket
Step-by-step explanation:
The probability of receive a speeding ticket in one of the traps is equal to the probability of going through that trap during the operation time of the trap.
Like we have four traps, and the probabilities are independent, then the probability of receive a speed ticket in one of them, is the sum of the probability for each trap.
P=P1+P2+P3+P4
The probability of going through a trap during the operation time is obtained by multiplying the probability of passing through the trap by the frequency of operation
Frequency of operation:
TL1 ⇒ 40 % = 0.4
TL2 ⇒ 30 % = 0.3
TL3 ⇒ 20 % = 0.2
TL4 ⇒ 30 % = 0.3
Probability of passing through these locations
PL1 ⇒ 0.3
PL2 ⇒ 0.2
PL3 ⇒ 0.4
PL4 ⇒ 0.1
then,
P1= TL1*PL1
P2= TL2*PL2
P3= TL3*PL3
P4= TL4*PL4
and
P = TL1*PL1 + TL2*PL2 + TL3*PL3 + TL4*PL4 = 0.12 + 0.06 + 0.08 + 0.03 = 0.29 = 29 %
This person have a 29 % probability to receive a speeding ticket
