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tigry1 [53]
3 years ago
11

Anyone know the correct answer

Mathematics
2 answers:
Mashutka [201]3 years ago
8 0

Answer:

8 036 here is answer

Step-by-step explanation:

I just calculated

vekshin13 years ago
5 0

Answer:

8,036 here is the answer

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In the rectangle below, EI = 2x+6, FI = 5x-6, and m ZIFE = 49º.
Reil [10]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Three apples weigh about a pound about how much would one apple cost round to the nearest tenth
7nadin3 [17]
3 apples weigh 1 lb.....so 1 apple would weigh 1/3 = 0.3 lbs
5 0
3 years ago
in the function y-1=1/2(x-6)^2 what effect does the number 6 have on the graph, as compared to the graph y=x^2
butalik [34]

Answer: The graph is shifted 6 units to the right.

Step-by-step explanation:

It is important to remember that:

When f(x-k), then the function is shifted "k" units to the right.

Knowing this and given the quadratic parent function y=x^2 and the function y-1=\frac{1}{2}(x-6)^2, you can observe that one of the transformations is the following:

f(x-k)

Where:

k=6

Therefore, you can notice that the effect is:

The graph is shifted 6 units to the right.

7 0
3 years ago
5 times what thousandths equals 0.045?
notka56 [123]
.009 is the answer to this equation
7 0
3 years ago
A randomized controlled study was designed to test whether regular drinking of cranberry juice can prevent the recurrence of uri
Kamila [148]

Answer:

1. The chi-squared statistic = 10.36

The degrees of freedom = 17

The p-value for the test = 0.89

2. The range of the p-value from the Chi squared table = 0.75 < p-value < 0.90

Step-by-step explanation:

1. The Chi squared test is given as follows;

\chi ^{2} = \sum \dfrac{\left (Observed - Expected  \right )^{2}}{Expected  }

Therefore,

                              UTI   No UTI    %     Total

Cranberry juice       8           42      84     50

Lactobacillus          19          30       61     49

Control                    18          30      60    50

The chi-squared statistic is given as follows;

\chi ^{2} = \dfrac{\left (8- 18\right )^{2}}{18} +  \dfrac{\left (42 - 30\right )^{2}}{30} = 10.36

The chi-squared statistic = 10.36

The degrees of freedom, df = 18 - 1 = 17 since the all of the expected count have a minimum value of 18

With the aid of the calculator we find the p value as p as follows;

p = 0.9 - \dfrac{10.36 - 10.085}{12.972 - 10.085} \times (0.9 - 0.75)

The p-value for the test = 0.89  

2. The range of the p-value from the Chi squared table is given as follows;

0.75 < p-value < 0.90.

5 0
3 years ago
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