Answer: it should be 5+3+4+11=23
Step-by-step explanation: when you look for the volume you add all the numbers. hope it helps :)
plz mark as branlist
Answer: C- 1139 cm cubed.
Step-by-step explanation:
Hope this helps
Answer:
By the Central Limit Theorem, both would be approximately normal and have the same mean. The difference is in the standard deviation, since as the sample size increases, the standard deviation decreases. So the SRS of 600 would have a smaller standard deviation than the SRS of 200.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For the sampling distribution of size n of a sample proportion p, the mean is p and the standard deviation is 
Differences between SRS of 200 and of 600
By the Central Limit Theorem, both would be approximately normal and have the same mean. The difference is in the standard deviation, since as the sample size increases, the standard deviation decreases. So the SRS of 600 would have a smaller standard deviation than the SRS of 200.
Answer:
44.4
Step-by-step explanation:
Since we have a right triangle, we can use trig functions
sin theta = opp / hyp
sin x = 7/10
Taking the inverse sin of each side
sin^-1 (sin x) = sin^-1(7/10)
x = 44.427
Rounding to the nearest tenth
x = 44.4
Answer:
The probability that at lest one job will be missed in 57 second is
=0.819134
Step-by-step explanation:
Poisson distribution:
A discrete random variable X having the enumerable set {0,1,2,....} as the spectrum, is said to be Poisson distribution.
for x=0,1,2...
λ is the average per unit time
Given that, a job arrives at a web server with the probability 0.03.
Here λ=0.03, t=57 second.
The probability that at lest one job will be missed in 57 second is
=P(X≥1)
=1- P(X<1)
=1- P(X=0)


=0.819134