Answer:
b= -1
Step-by-step explanation:
48 =. 56 +8b
-56 -56
---------------------------------
-8 = 8b
Divide 8 on both sides
-1=b
Answer:
Step-by-step explanation:
Given that cesar left the college traveling 12 mph. Then, 4 hours later, Gabriel left traveling the same direction at 24 mph.
Before Gabriel started Cesar would have travelled for 4 hours
So distance travelled by Cesar in 4 hours 
Thus Cesar is ahead of Gabriel by 48 miles
Difference of speed 
So to catch Cesar time required = 48/difference in speed
= 4 hours
It will take 4 hours.
Answer:
I would be 21 for the missing side
To make it easier, you calculate the volume of the first aquarium.
1st aquarium:
V = L x W x H
V = 8 x 9 x 13
V = 72 x 13
V = 936 in.
Rate: 936 in./2 min.
Now that you've got the volume and rate of the first aquarium, you can find how many inches of the aquarium is filled within a minute, which is also known as the unit rate. To do that, you have to divide both the numerator and denominator by their least common multiple, which is 2. 936 divided by 2 is 468 and 2 divided by 2 is 1.
So the unit rate is 468 in./1 min. Now that you've got the unit rate, you can find out how long it'll take to fill the second aquarium up by finding its volume first.
2nd aquarium:
V = L x W x H
V = 21 x 29 x 30
V = 609 x 30
V 18,270 inches
Calculations:
Now, you divide 18,270 by 468 to find how many minutes it will take to fill up the second aquarium. 18,270 divided by 468 is about 39 (the answer wasn't exact, so I said "about").
2nd aquarium's rate:
18,270 in./39 min.
As a result, it'll take about 39 minutes to fill up an aquarium measuring 21 inches by 29 inches by 30 inches using the same hose. I really hope I helped and that you understood my explanation! :) If I didn't, I'm sorry. I tried. :(
To find how long it would take him, one has to divide 400 by 160 and then multiply 5 by what that number is. You multiply 5 by the quotient because that is the number that would make it proportional. 400/160 x 5 is 12.5, meaning that the answer is 12.5 minutes, or A.
