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Neporo4naja [7]
3 years ago
7

Which is not a solution of the inequality?

Mathematics
1 answer:
Soloha48 [4]3 years ago
4 0

Answer:

Answer= -4 hope it helps

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Fractions are hard... Or I'm just to lazy to try and do them.
notka56 [123]
Answer: C) 3/2

Explanation: In math, the reciprocal is the inverse of a number or value. Simply, the number when flipped. Knowing this, one can flip the fraction to find the reciprocal, in this case turning 2/3 into 3/2.

Hope this helps :)
5 0
3 years ago
Is 1.21221222 a rational number
trapecia [35]

Answer:

i think no i think lng po ehh

8 0
3 years ago
Read 2 more answers
The function<img src="https://tex.z-dn.net/?f=f%28x%29%3D-3x%5E%7B3%7D%20%2Bx%5E%7B2%7D%20%2B2x" id="TexFormula1" title="f(x)=-3
musickatia [10]

Answer:

True

Step-by-step explanation:

True.

Like the cubic term -3x^3 is negative, for small values of "x", the dependent variable "y" will rise. All this can be verified by looking at the graph.

6 0
3 years ago
6. What is the result of multiplying the digit in the hundredths place by
Setler [38]

Answer:

B.9

Step-by-step explanation:

9*1=9

6 0
3 years ago
Two 5-year girls, Alyse and Jocelyn, have been training to run a 1-mile race. Alyse's 1 mile time A is approximately Normally di
tatyana61 [14]

Answer:

1.7 × 10⁻⁴

Step-by-step explanation:

The question relates to a two sample z-test for the comparison between the means of the two samples  

The null hypothesis is H₀:  μ₁ ≤ μ₂

The alternative hypothesis is Hₐ: μ₁ > μ₂

z=\dfrac{(\bar{x}_1-\bar{x}_2)-(\mu_{1}-\mu _{2} )}{\sqrt{\dfrac{\sigma_{1}^{2} }{n_{1}}-\dfrac{\sigma _{2}^{2}}{n_{2}}}}

Where;

\bar {x}_1 = 13.5

\bar {x}_2 = 12

σ₁ = 2.5

σ₂ = 1.5

We set our α level at 0.05

Therefore, our critical z = ± 1.96

For n₁ = n₂ = 23, we have;

z=\dfrac{(13.5-12)-(0)}{\sqrt{\dfrac{2.5^{2} }{23}-\dfrac{1.5^{2}}{23}}} = 3.5969

We reject the null hypothesis at α = 0.05, as our z-value, 3.5969 is larger than the critical z, 1.96 or mathematically, since 3.5969 > 1.96

Therefore, there is enough statistical evidence to suggest that Alyse time is larger than Jocelyn in a 1 mile race on a randomly select day and the probability that Alyse has a larger time than Jocelyn is 0.99983

Therefore;

The probability that Alyse has a smaller time than Jocelyn is 1 - 0.99983 = 0.00017 = 1.7 × 10⁻⁴.

8 0
3 years ago
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