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saul85 [17]
3 years ago
8

N is the middle integer of three consecutive positive integers.

Mathematics
1 answer:
abruzzese [7]3 years ago
6 0

Answer :

\boxed{\textsf{ The final answer is \textbf{n}$^{\textbf{3}}$ .}}

Step-by-step explanation:

Its given that n is the middle out of the three consecutive integers . So ,

<u>The </u><u>last</u><u> </u><u>integer</u><u> </u><u>will</u><u> </u><u>be</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies Last \ Integer \ = \ n - 1

<u>The </u><u>next</u><u> </u><u>Integer</u><u> </u><u>will</u><u> be</u><u> </u><u>:</u><u>-</u>

\sf\implies Next \ Integer \ = \ n + 1

Now the Question says that the three integers are multipled to give a product . So that would be.

\sf\implies Product_{(three\ consecutive\ integers)}= (n-1)n(n+1) = (n^2-1)(n) = \pink{n^3-n}

Now thirdly it's given that n is added to the given integer . That would be ,

\sf\implies Adding\ n = \ n^3 - n + n = \pink{n^3}

Here - n and +n gets cancelled. So we are ultimately left out with n³.

Hence the final number is a cube of some number.

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