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2 years ago

Ax+ By =z how to solve for y?

Mathematics

2 answers:

Trava [24]2 years ago

8 0

Answer:

Ax+BY=z First subtract Ax from both sides to get By=z-Ax. Then divide by B from both side to get y=(z-Ax)/B

Step-by-step explanation:

mixas84 [53]2 years ago

5 0

Answer:

y = (z-Ax)/B

Step-by-step explanation:

Ax+ By =z

Subtract Ax from each side

Ax-Ax+ By =z-Ax

By = z-Ax

Divide each side by B

By/B = (z-Ax)/B

y = (z-Ax)/B

You might be interested in

Which ordered pairs make both inequalities true? Select two options. y < 5x + 2 y > One-halfx + 1 On a coordinate plane, 2

Verdich [7]

Answer:

(1, 2)

(2,2)

Step-by-step explanation:

The inequality Given :

y < 5x + 2

y ≥ One-halfx + 1

We can use the values in the options to see which satisfies the inequality :

(-1, 3) ; X = - 1, y = 3

3 < 5(-1) + 2 ; 3 < - 4 (not true)

(0, 2) ; X = 0 ; y = 2

2 < 5(0) + 2 ; 2 < 2 (nor true)

2 > 1/2(0) + 1

2 > 1 (true)

Using (1, 2).; x = 1 ; y = 2

2 < 5(1) + 2 ; 2 < 7 (true)

2 > 1/2(1) + 1 ; 2 > 1.5 (true)

Using (2, 2)

y < 5x + 2

2 < 10 + 2 ; 2 < 12 (true)

y > 1/2x + 1

2 > 1/2(2) + 1 ; 2

8 0

2 years ago

Help with this question ASAP!

user100 [1]

Answer:

After 4s

Step-by-step explanation:

Given the ball is initially projected upwards with a velocity of 64ft per sec and we are required to find the time at which it reaches the ground .There are many approaches to solve this problem we will follow this one:

It is also known as the time of flight for the ball which can be found by doubling the time taken for the ball to reach to its maximum height or the point where velocity is zero.

Now $h(t)=-16\times t^{2} +v_{0} \times t+h_{0}$