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Lena [83]
3 years ago
9

Which expression best estimates – 184-2į? O 18-3 -18-3 0-18-(-3) O 18-(-3)

Mathematics
1 answer:
nikitadnepr [17]3 years ago
5 0
The best one is 18-3
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Please answer! 40 points! (It will give you half of that)
SVETLANKA909090 [29]

Answer:

1-1

2-2

3-4

4-3

5-6

6-5

Step-by-step explanation:

Just simplify each equation to its simplest form

eg,: #1

4/3 = 1 1/3

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4 years ago
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100 POINTS!!! PLEAAASSEEE HELP ME!!!!
DIA [1.3K]

Answer:

2/3 = 5/8

Step-by-step explanation:

If two figures are similar, then the ratio of its corresponding sides is equal and is called the scale factor

In this problem

2/3 = 5/8 -----> is not true

therefore

The figures are not similar

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3 years ago
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Sam is filling up his pool. The water hose filled the 315 gallon pool in 45 minutes. At what rate did the hose fill the pool in
Serhud [2]

Answer:

7 gallons per minute

Step-by-step explanation:

315/45 = 7

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3 years ago
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(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?
DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500

  • There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111

  • There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611

7 0
3 years ago
The school store sells Midville High T-shirts for $12 each and Midville High shorts for $9 a pair. One afternoon they sold a tot
Flura [38]

Answer:
There will be 22 pairs of shorts were sold at a price of $9 each.

5 0
3 years ago
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