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Alekssandra [29.7K]

2 years ago

11

Please answer question a & b.

1 answer:

Paul [167]2 years ago

5 0

Answer:

a)

b)0.1

pls refer to the pic

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WILL GIVE BRAINLIEST IF CORRECT! I'm timed plz Help

lesantik [10]

Answer:

C. q Superscript 12

Step-by-step explanation:

$q \: Superscript \: 12 = {q}^{12} = { ({q}^{6})}^{2} \\$

4 0

2 years ago

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I need help with 6,7 pleaaseee

antiseptic1488 [7]

6. addition property of equality (because 7 was added to each side)

7. A function has no repeating x values.....so the one that is not a function WILL HAVE repeating x values......and that would be C because it has repeating 2's

5 0

2 years ago

2. At the mall, Leona bought a T-shirt and a book for a total of $23. The book cost $12. How much did the T-shirt cost?

enyata [817]

11 because you have to add from 12 to get to 23

7 0

3 years ago

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Use arrow notation to describe the translation of point PC-9, 5) to point P4-6, 7).

Akimi4 [234]

Thank you lord lord thank lord lord

5 0

3 years ago

My Notes OAsk Your Tea The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t an

Papessa [141]

Answer:

10.96 hours will take for 85% of the lead to decay.

Step-by-step explanation:

Suppose A represents the amount of Pb-209 at time t,

According to the question,

$\frac{dA}{dt}\propto A$

$\implies \frac{dA}{dt}=kA$

$\int \frac{dA}{A}=\int kdt$

$ln|A|=kt+C_1$

$A=e^{kt+C_1}$

$A=e^{C_1} e^{kt}$

$\implies A=C e^{kt}$

Let $A_0$ be the initial amount,

$A_0=C e^{0} = C$

$\implies A=A_0 e^{kt}$

Since, the half-life of 3.3 hours.

$\implies \frac{A_0}{2}=A_0 e^{3.3k}\implies e^{3.3k}=0.5\implies k=-0.21004$

$\implies A=A_0 e^{-0.21004t}$

Here, $A_0=1\text{ gram}$

$A=(100-85)\% \text{ of }A_0=15\%\text{ of }A_0=0.15A_0$

By substituting the values,

$0.15A_0=A_0 e^{-0.21004t}$

$0.15=e^{-0.21004t}$

$\implies t\approx 10.96\text{ hour}$

6 0

2 years ago