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2 years ago

Please helpppppppppppppppppppppppppppppppppppp

Mathematics

2 answers:

Kay [80]2 years ago

7 0

Answer:

(THIRD/FOURTH QUESTION): 4,000,000/4,096,000,000

Step-by-step explanation:

Third:

10x10x10x10x10= 100,000

100,000x40= 4,000,000

Fourth:

40x40x40x40x40x40= 4,096,000,000

Pani-rosa [81]2 years ago

6 0

Step-by-step explanation:

(2×10^8)(2×10^-2)
4×10^8+(-2)
4×10^6

<h3>stay safe healthy and happy.</h3>

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3/5 of 300 is 180. 180 coupons were unused.

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3 years ago

Determine the median of the following numbers: 8, 11, 11, 12, 13, 15, 16, 16, 18, 21

Fiesta28 [93]

The median of the following numbers is 14

Order the numbers from least to greatest
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3 years ago

Read 2 more answers

To convert a fraction to a decimal, you have to divide ________ by the _________?

Burka [1]

To convert a fraction to a decimal, you have to divide the denominator by the numerator.

<em>HOPE THIS HELPS! HAVE A GREAT DAY!!!</em>

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2 years ago

Read 2 more answers

Line AB and line CD intersect at point E, with point E between A and B and between C and D. Which rays are opposite rays?

olchik [2.2K]

Answer:

EA, EB, EC and ED are opposites rays.

Step-by-step explanation:

Given that,

Line AB and line CD intersect at point E.

According to figure,

We need to find opposite rays

Using diagram

We draw a first line AB and second line CD which is intersect of AB at point E.

Now, EA and EB is called opposite ray of first line AB.

Similarly,

EC and ED is called opposite ray of first line CD.

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3 0

3 years ago

There are 158 students registered for American History classes. There are twice as many students registered in second period as

Margarita [4]

There are 28 students in first period and 56 students in sceond period and 74 students in third period

<em><u>Solution:</u></em>

Let the number of students in first period be "x"

Let the number of students in second period be "y"

Let the number of students in third period be "z"

<em><u>There are 158 students registered for American History classes.</u></em>

Therefore,

x + y + z = 158 ---------- eqn 1

<em><u>There are twice as many students registered in second period as first period</u></em>

number of students in second period = twice of number of students in first period

y = 2x ------- eqn 2

<em><u>There are 10 less than three times as many students in third period as in first period</u></em>

number of students in third period = 3 times number of students in first period - 10

z = 3x - 10 ------ eqn 3

<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>

x + 2x + 3x - 10 = 158

6x = 168

<em><u>Substitute x = 28 in eqn 2</u></em>

y = 2(28)

<em><u>Substitute x = 28 in eqn 3</u></em>

z = 3(28) - 10

z = 84 - 10

Thus there are 28 students in first period and 56 students in sceond period and 74 students in third period

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2 years ago