Correct question:
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 131 millimeters, and a standard deviation of 7 millimeters. If a random sample of 31" steel bolts is selected, what is the probability that the sample mean would differ from the population mean by more than 1.9 millimeters? Round your answer to four decimal places.
Answer:
0.1310
Step-by-step explanation:
Given:
Sample size, n = 31
mean, u = 131
X - u = 1.9
If a random sample of 31 steel bolts is selected, the probability that the sample mean would differ from the population mean by more than 1.9 millimeter, would be determined by:
Z = 1.51
Probability =
P(|Z| > 1.51) =
P(Z < -1.51) + P(Z > 1.51)
= P(Z < -1.51) + 1 - P(Z > 1.51)
Using the standard normal table:
= NORMDIST(-1.51) = 0.0655;
NORMDIST(1.51) = 0.9345
Thus,
P = 0.0655 + 1 - 0.9345
= 0.1310
This sample size it too small. The larger the sample size, the more likely the data will be true to what the question is asking. A larger sample size brings more precision to the question that is being asked.
The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
Answer:
34 cans. If you set it up as ratios (5/2.85 = x/19.38), make the number of cans you need to know "x" and solve for x.
We have the following:
To organize the number from least to greastest, we must look at the decimals in this case, since they all start with 6
Therefore the order of the numbers is
