A statement which correctly compares the two functions on the given interval [-1, 2] is: C. Both functions are increasing, but function g increases at a faster average rate.
<h3>How to compares the two functions?</h3>
First of all, we would determine the values of function g(x) on the given interval [-1, 2] as follows:
g(x) = -18(⅓)^x + 2
At x = -1, we have:
g(-1) = -18(⅓)^(-1) + 2
g(-1) = -52.
At x = 0, we have:
g(0) = -18(⅓)^(0) + 2
g(0) = -16.
At x = 1, we have:
g(1) = -18(⅓)^(1) + 2
g(1) = -4.
At x = 2, we have:
g(2) = -18(⅓)^(0) + 2
g(2) = 0.
By critically observing the values of each functions, we can logically deduce that both functions are increasing but function g(x) increases at a faster average rate because it started with a lower value and ended with a higher value.
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Answer:
Option B
Step-by-step explanation:
log x=2
x = 10^2
Therefore, the exponential form is the one in option B
The value of the game will be $ 0.08. Then the correct option is B.
<h3>What is probability?</h3>
Its simple notion is that something will most likely occur. The favorable event's proportion to the overall number of occurrences.
A game is played by rolling a fair six-sided die once.
If the die lands on a 1 the player win $8 otherwise the player loses $1.50.
Then the value of the game will be
The probability of success will be
p = 1/6
The probability of failure will be
p = 5/6
Then the value of the game will be
Value of game = 8p - 1.5q
Value of game = 8 x 1/6 - 1.5 x 5/6
Value of game = 1.3333 - 1.25
Value of game = 0.08333
Value of game ≅ $ 0.08
More about the probability link is given below.
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C I think if not b have a good day