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3 years ago

11 1/9 - 6 2/3 pease anwer

Mathematics

2 answers:

Virty [35]3 years ago

8 0

Answer:

Step-by-step explanation:

Rewriting our equation with parts separated:

= 11 + 1/9 - 6 - 2/3

Solving the whole number parts:

11 - 6 = 5

solving the fraction parts:

1/9 - 2/3 = ?

Find the LCD of 1/9 and 2/3 and rewrite to solve with the equivalent fractions.

LCD = 9

1/9 - 6/9 = - 5/9

Combining the whole and fraction parts:

5 - 5/9 = 4 4/9

rosijanka [135]3 years ago

7 0

4 5/9 this is the answer to your question

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Read 2 more answers

Solve using the quadratic formula 2x^2+x+67=0

telo118 [61]

Answer:

$\displaystyle x=\frac{-1 \pm i\sqrt{535}}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Multiple Roots
Standard Form: ax² + bx + c = 0
Quadratic Formula: $\displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

Algebra II

Imaginary Root i = √-1

Step-by-step explanation:

Step 1: Define

Identify

2x² + x + 67 = 0

a = 2

b = 1

c = 67

Step 2: Solve for x

Substitute in variables [Quadratic Formula]: $\displaystyle x=\frac{-1 \pm \sqrt{1^2-4(2)(67)}}{2(1)}$
Multiply: $\displaystyle x=\frac{-1 \pm \sqrt{1^2-4(2)(67)}}{2}$
[√Radical] Evaluate exponents: $\displaystyle x=\frac{-1 \pm \sqrt{1-4(2)(67)}}{2}$
[√Radical] Multiply: $\displaystyle x=\frac{-1 \pm \sqrt{1-536}}{2}$
[√Radical] Subtract: $\displaystyle x=\frac{-1 \pm \sqrt{-535}}{2}$
[√Radical] Simplify: $\displaystyle x=\frac{-1 \pm i\sqrt{535}}{2}$