Answer: First number 3 Second 18
Step-by-step explanation:
Answer: £164.50
175 decreased by 6% = 164.5
Absolute change (actual difference):
164.5 - 175 = - 10.5
Step-by-step explanation:
175 - Percentage decrease =
175 - (6% × 175) =
175 - 6% × 175 =
(1 - 6%) × 175 =
(100% - 6%) × 175 =
94% × 175 =
94 ÷ 100 × 175 =
94 × 175 ÷ 100 =
16,450 ÷ 100 =
164.5
£164.50
Answer:
a.Z(-2,1)
b.Z(1,1)
c.Z(-3,2)
Step-by-step explanation:
z(-2,3)
Imagine this point on a graph.
Translate it down two units :
the x stays -2, by going down the y decreases 2 so 3-2=1
Z(-2,1)
Translate Right three units : I'm assuming that we use the answer from the first translation
Z(-2,1)
The y doesn't change this time the x increases 3 since we're moving to the right.
Z(1,1)
Translate up 1 and left 4:
Z(1,1)
by moving up one we have Z(1,2) then by moving 4 to the left we get Z(-3,2)
Hope this helps :)
Answer:

Step-by-step explanation:
Hello,
a and b are the zeros, we can say that

So we can say that

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b
for instance we can write

and we can notice that
so
![(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab](https://tex.z-dn.net/?f=%28x-2a-3b%29%28x-3a-2b%29%3Dx%5E2-5%28a%2Bb%29x%2B6%5B%28a%2Bb%292-2ab%5D%2B13ab%5C%5C%3D%20x%5E2-5%28a%2Bb%29x%2B6%28a%2Bb%29%5E2%2Bab)
it comes

multiply by 3

Answer:
<u>Using below system of inequalities</u>
<u>Following the rules </u>
- 1. Finding x- and y - intercepts
- 2. Connecting with dotted line for each as no equal symbol present in any inequality
- 3. Shade respective regions
- 4. Solution is the intersection of the shades regions
- 5. Select any three points in the solution region
<u>Line 1</u>
- y > 2x - 3
- x- intercept: y = 0 ⇒ 0 = 2x - 3 ⇒ 2x = 3 ⇒ x = 1.5
- y - intercept: x = 0 ⇒ y = -3
- Shaded region is above the line (or to the left)
<u>Line 2</u>
- y < x + 1
- x- intercept: y = 0 ⇒ 0 = x + 1 ⇒ x = -1
- y - intercept: x = 0 ⇒ y = 1
- Shaded region is below the line (or to the right)
<u>Selected points are:</u>