<em>A player has made 188 free throw attempts, and in that time has made a total of 129 free throws. FT % = 0.686 Therefore, this player has an FT% of .686, or 68.6%. Wikipedia – Free throw percentage season leaders and Free Throw (Basketball) – Wikipedia entries on the concept of free throws.</em>
Answer:
2.65
Step-by-step explanation:
Multiply each payout by its probability, then add those products.
See the attached image.
The first column has the payouts. The second column has the probabilities. The third column has the results of multiplying a payout by its probability.
The sum of the entries in the third column is 2.65
I think its that jason mathed wrong