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MrRissso [65]
3 years ago
14

Analyze the diagram below and complete the instructions that

Mathematics
1 answer:
8090 [49]3 years ago
6 0

Answer:

The shape is a square and a triangle, so all sides of the square are equal to 6, and applying the Pythagorean law to a right-angled triangle, we can find the value of x

Then

{x}^{2}  =  {6}^{2}  +  {3 }^{2}  \\  {x}^{2}  = 36 + 9 \\  {x}^{2}  = 45 \\ x = 3 \sqrt{5}

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Biologists have found that the number of chirps some crickets make per minute is related to temperature. The relationship is ver
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Answer:

  points (x, y) = {(124, 68), (172, 80)}

  y = 1/4x +37

Step-by-step explanation:

For the variable definitions given, the problem statement gives you the points ...

  (chirps, temperature) = (x, y) = (124, 68)  or  (172, 80)

__

You are asked to find a linear equation that relates x and y.

The slope can be found using the slope formula:

  m = (y2 -y1)/(x2 -x1)

  m = (80 -68)/(172 -124) = 12/48 = 1/4

The y-intercept can be found from ...

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3 0
2 years ago
Pls solve this question ​
just olya [345]

Answer:

{( \sqrt{ {x}^{ - 3} }) }^{5}  =  ({( {x}^{ - 3}) }^{ \frac{1}{2} } ) ^{5}  \\  \\  =  {x}^{ - 3 \times  \frac{1}{2}  \times 5}   =  {x}^{  -  \frac{15}{2} }  =  \frac{1}{ {x}^{ \frac{15}{2} } }

<em><u>Or ;</u></em>

{( \sqrt{ {x}^{ - 3} } )}^{5}  =  {( \sqrt{ \frac{1}{ {x}^{3} }} })^{5}  = ( { \frac{ \sqrt{1} }{ \sqrt{ {x}^{3} } } })^{5}  \\  \\  =  ( { \frac{1}{ \sqrt{x}  \sqrt{ {x}^{2} } } })^{5}  =  ({ \frac{1}{ x\sqrt{x} }})^{5}   \\  \\  = ( \frac{ {(1)}^{5} }{ {x}^{5} ( \sqrt{x} )^{5} } ) =  \frac{1}{ {x}^{5}  \times  {x}^{ \frac{1}{2} \times 5 } }  \\  \\  =  \frac{1}{ {x}^{5}  \times  {x}^{ \frac{5}{2} } }  =  \frac{1}{ {x}^{5}  \sqrt{ {x}^{5} } }  \\  \\  =  \frac{1}{ {x}^{5} \sqrt{ {x}^{4} {x}^{1}  }  }  =  \frac{1}{ {x}^{5}  \sqrt{x}  \sqrt{( { {x}^{2} })^{2} } }  \\  \\  =  \frac{1}{ {x}^{5} {x}^{2}  \sqrt{x}  }  =  \frac{1}{ {x}^{7} \sqrt{x}  }   =  \frac{ \sqrt{x} }{ {x}^{8} }

3 0
2 years ago
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