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3 years ago

14

Analyze the diagram below and complete the instructions that

1 answer:

8090 [49]3 years ago

6 0

Answer:

The shape is a square and a triangle, so all sides of the square are equal to 6, and applying the Pythagorean law to a right-angled triangle, we can find the value of x

Then

${x}^{2} = {6}^{2} + {3 }^{2} \\ {x}^{2} = 36 + 9 \\ {x}^{2} = 45 \\ x = 3 \sqrt{5}$

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Determine the measures of the angles requested using the picture below.<br>

lapo4ka [179]

SHDJJEHEH shdhshshshshduvuvuvububuyb

5 0

3 years ago

6x+3<7-2x<br> I’m not sure if I’m doing it right so an explanation would be nice

enot [183]

Answer:

x<0.5

Step-by-step explanation:

this is just like simplifiying equations if you've done that before

first you want to isolate the variable, so you want to combine the values of x (in this case it's 6x and the -2x)

so you can either add 2x to both sides or you can subtract 6x on both sides, in this case ill just add 2x to both sides.

Then you subtract 3 from both sides to get 8x<4

after you get that, you want to divide both sides by 8, and you generally want to do that step last, it makes it easier, and you get x<1/2 or 0.5

just a reminder that with working with inequalities, you want to remember to flip the direction the inequality is whenever you divide by a negative number

7 0

3 years ago

Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a sprin

vlada-n [284]

Answer:

The work done is 202.50Nm

Step-by-step explanation:

Given

$F =450N$

$x_1 = 30cm$

$x_2 = 60cm$

Required

The work done

First, we calculate the spring constant (k)

$F = kx_1$

$450N = k *30cm$

$k = \frac{450N}{30cm}$

$k =15N/cm$

So:

$F = kx_1$

$F(x) = 15x$

The work done using Hooke's law is:

$W =\int\limits^a_b {F(x)} \, dx$

This gives:

$W =\int\limits^{60}_{30} {15x} \, dx$

Rewrite as:

$W =15\int\limits^{60}_{30} {x} \, dx$

Integrate

$W =15 \frac{x^2}{2}|\limits^{60}_{30}$

This gives:

$W =15 *\frac{60^2 - 30^2}{2}$

$W =15 *\frac{2700}{2}$

$W =15 *1350$

$W =20250N-cm$

Convert to Nm

$W =\frac{20250Nm}{100}$

$W =202.50Nm$

7 0

3 years ago

In a group of a hundred and fifty students attending a youth workshop in mombasa, 125 of them are fluent in kiswahili, 135 in en

jek_recluse [69]

Answer:

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given total number of students n(T) = 150

Given 125 of them are fluent in Swahili

Let 'S' be the event of fluent in Swahili language

n(S) = 125

The probability that the fluent in Swahili language

$P(S) = \frac{n(S)}{n(T)} = \frac{125}{150} = 0.8333$

Let 'E' be the event of fluent in English language

n(E) = 135

The probability that the fluent in English language

$P(E) = \frac{n(E)}{n(T)} = \frac{135}{150} = 0.9$

n(E∩S) = 95

The probability that the fluent in English and Swahili

$P(SnE) = \frac{n(SnE)}{n(T)} = \frac{95}{150} = 0.633$

<u><em>Step(ii):</em></u>-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = P(S) + P(E) - P(S∩E)

= 0.833+0.9-0.633

= 1.1

<u><em>Final answer:-</em></u>

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

8 0

3 years ago

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goblinko [34]

Here is your answer

8 0

3 years ago

Read 2 more answers