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3 years ago

PLEASE I GIVE BRAINLIRST PLEASE HELP I NEED TO OASS THIS

Mathematics

1 answer:

aalyn [17]3 years ago

7 0

Answer:

Evan needs enough paint to cover 448in^2

He needs enough soil to fill 768in^3

Step-by-step explanation:

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Find the area of a square with side lengthd of 5 4 inches

mr Goodwill [35]

A=2916, you take 54 and square it

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3 years ago

Petra jogs 3 miles in 30 minutes at this rate how long would it take a jog 10 miles

bazaltina [42]

Answer:

100 minutes or 1 hour and 40 minutes

Step-by-step explanation:

3 miles in 30 minutes means 1 mile in 10 minutes

10 miles takes 100 minutes or 1 hour and 40 minutes.

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3 years ago

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Solve for x (21x-9) 27 x=

garik1379 [7]

Answer:

3(7x-3)

Step-by-step explanation: I factor it.

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2 years ago

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Maggie graphed the image of a 90 counterclockwise rotation about vertex A of . Coordinates B and C of are (2, 6) and (4, 3) and

Lemur [1.5K]

Answer:

A(2,2)

Step-by-step explanation:

Let the vertex A has coordinates $(x_A,y_A)$

Vectors AB and AB' are perpendicular, then

$\overrightarrow {AB}=(2-x_A,6-y_A)\\ \\\overrightarrow {AB'}=(-2-x_A,2-y_A)\\ \\\overrightarrow {AB}\perp\overrightarrow {AB'}\Rightarrow \overrightarrow {AB}\cdot \overrightarrow {AB'}=0\Rightarrow (2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0$

Vectors AC and AC' are perpendicular, then

$\overrightarrow {AC}=(4-x_A,3-y_A)\\ \\\overrightarrow {AC'}=(1-x_A,4-y_A)\\ \\\overrightarrow {AC}\perp\overrightarrow {AC'}\Rightarrow \overrightarrow {AC}\cdot \overrightarrow {AC'}=0\Rightarrow (4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0$

Now, solve the system of two equations:

$\left\{\begin{array}{l}(2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0\\ \\(4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0\end{array}\right.\\ \\\left\{\begin{array}{l}-4-2x_A+2x_A+x_A^2+12-6y_A-2y_A+y^2_A=0\\ \\4-4x_A-x_A+x_A^2+12-3y_A-4y_A+y_A^2=0\end{array}\right.\\ \\\left\{\begin{array}{l}x_A^2+y_A^2-8y_A+8=0\\ \\x_A^2+y_A^2-5x_A-7y_A+16=0\end{array}\right.$

Subtract these two equations:

$5x_A-y_A-8=0\Rightarrow y_A=5x_A-8$

Substitute it into the first equation:

$x_A^2+(5x_A-8)^2-8(5x_A-8)+8=0\\ \\x_A^2+25x_A^2-80x_A+64-40x_A+64+8=0\\ \\26x_A^2-120x_A+136=0\\ \\13x_A^2-60x_A+68=0\\ \\D=(-60)^2-4\cdot 13\cdot 68=3600-3536=64\\ \\x_{A_{1,2}}=\dfrac{60\pm8}{2\cdot 13}=\dfrac{34}{13},2$

Then

$y_{A_{1,2}}=5\cdot \dfrac{34}{13}-8 \text{ or } 5\cdot 2-8\\ \\=\dfrac{66}{13}\text{ or } 2$

Rotation by 90° counterclockwise about A(2,2) gives image points B' and C' (see attached diagram)

8 0

3 years ago

Match the values associated with this data set to their correct descriptions.

Klio2033 [76]

The correct matches are as follows:

quartile

10.5

median
41

third quartile
38.5

the difference of the largest value and the median
49-41 = 8

Hope this answers the question. Have a nice day. Feel free to ask more question.

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3 years ago

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