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lidiya [134]
3 years ago
12

PLEASE I GIVE BRAINLIRST PLEASE HELP I NEED TO OASS THIS

Mathematics
1 answer:
aalyn [17]3 years ago
7 0

Answer:

Evan needs enough paint to cover 448in^2

He needs enough soil to fill 768in^3

Step-by-step explanation:

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Find the area of a square with side lengthd of 5 4 inches
mr Goodwill [35]
A=2916, you take 54 and square it 

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3 years ago
Petra jogs 3 miles in 30 minutes at this rate how long would it take a jog 10 miles​
bazaltina [42]

Answer:

100 minutes or 1 hour and 40 minutes

Step-by-step explanation:

3 miles in 30 minutes means 1 mile in 10 minutes

10 miles takes 100 minutes or 1 hour and 40 minutes.

7 0
3 years ago
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Solve for x<br>(21x-9)<br>27<br>x=​
garik1379 [7]

Answer:

3(7x-3)

Step-by-step explanation: I factor it.

5 0
2 years ago
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Maggie graphed the image of a 90 counterclockwise rotation about vertex A of . Coordinates B and C of are (2, 6) and (4, 3) and
Lemur [1.5K]

Answer:

A(2,2)

Step-by-step explanation:

Let the vertex A has coordinates (x_A,y_A)

Vectors AB and AB' are perpendicular, then

\overrightarrow {AB}=(2-x_A,6-y_A)\\ \\\overrightarrow {AB'}=(-2-x_A,2-y_A)\\ \\\overrightarrow {AB}\perp\overrightarrow {AB'}\Rightarrow \overrightarrow {AB}\cdot \overrightarrow {AB'}=0\Rightarrow (2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0

Vectors AC and AC' are perpendicular, then

\overrightarrow {AC}=(4-x_A,3-y_A)\\ \\\overrightarrow {AC'}=(1-x_A,4-y_A)\\ \\\overrightarrow {AC}\perp\overrightarrow {AC'}\Rightarrow \overrightarrow {AC}\cdot \overrightarrow {AC'}=0\Rightarrow (4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0

Now, solve the system of two equations:

\left\{\begin{array}{l}(2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0\\ \\(4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0\end{array}\right.\\ \\\left\{\begin{array}{l}-4-2x_A+2x_A+x_A^2+12-6y_A-2y_A+y^2_A=0\\ \\4-4x_A-x_A+x_A^2+12-3y_A-4y_A+y_A^2=0\end{array}\right.\\ \\\left\{\begin{array}{l}x_A^2+y_A^2-8y_A+8=0\\ \\x_A^2+y_A^2-5x_A-7y_A+16=0\end{array}\right.

Subtract these two equations:

5x_A-y_A-8=0\Rightarrow y_A=5x_A-8

Substitute it into the first equation:

x_A^2+(5x_A-8)^2-8(5x_A-8)+8=0\\ \\x_A^2+25x_A^2-80x_A+64-40x_A+64+8=0\\ \\26x_A^2-120x_A+136=0\\ \\13x_A^2-60x_A+68=0\\ \\D=(-60)^2-4\cdot 13\cdot 68=3600-3536=64\\ \\x_{A_{1,2}}=\dfrac{60\pm8}{2\cdot 13}=\dfrac{34}{13},2

Then

y_{A_{1,2}}=5\cdot \dfrac{34}{13}-8 \text{ or } 5\cdot 2-8\\ \\=\dfrac{66}{13}\text{ or } 2

Rotation by 90° counterclockwise about A(2,2) gives image points B' and C' (see attached diagram)

8 0
3 years ago
Match the values associated with this data set to their correct descriptions.
Klio2033 [76]
The correct matches are as follows:

quartile

10.5

<span>median
41

third quartile
</span>38.5<span>

the difference of the largest value and the median
49-41 = 8

Hope this answers the question. Have a nice day. Feel free to ask more question.

</span>
7 0
3 years ago
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