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liberstina [14]
4 years ago
13

P= a+b+2c solve for c

Mathematics
1 answer:
Inessa05 [86]4 years ago
4 0
                    P = a + b + 2c
          P - a - b = a - a + b - b + 2c
          P - a - b = 2c
                 2         2
¹/₂P - ¹/₂a - ¹/₂b = c
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Since they want a product, that means multiplication. We want to multiply a whole number and a fraction to get 5/3. When we multiply fractions, you multiply across the numerator and across the denominator. So in this case we want to multiply 2 numbers to get 5 a decimal 2 numbers to get 3. Each of these numbers only have 2 factors so
5 × 1 = 5 and
3 × 1 = 3

So we are going to multiply

5 × 1/3 =
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<h2>Problem 6:</h2><h2>a)</h2>

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a(3) = b(2) + c(2) =  8 + 9 = 17\\ b(3) = a(2) + c(2) =7 + 9 = 16  \\ c(3) = a(2) + b(2) = 7 + 8 = 15 \\  \\ a(4) = b(3) + c(3) = 16  + 15 = 31 \\ b(4) = a(3) + c(3) = 17 + 15 = 32 \\ c(4) = a(3) + b(3) = 17 + 16 = 33

a(5) = 32 + 33 = 65 \\ b(5) = 31 + 33 = 64 \\ c(5) =31 + 32 =  63 \\  \\ a(6) = 64 + 63 = 127 \\ b(6) = 65 + 63 = 128 \\ c(6) = 65 + 64 = 129 \\

a(7) = 128 + 129 = 257 \\ b(7) = 127 + 129 = 256 \\c (7) = 127 + 128 = 255 \\  \\ a(8) = 256 + 255 = 511 \\ b(8) = 257 + 255 = 512 \\ c(8) = 257 + 256 = 513

a(9) = 512 + 513 = 1025 \\ b(9) = 511 + 513 = 1024 \\ c(9) = 511 + 512 = 1023 \\  \\ a(10) = 1024 + 1023 = 2047 \\ b(10) = 1025  + 1023 = 2048 \\ c(10) = 1025 + 1024 = 2049

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a(n) + b(n) + c(n) =   \\  2(a(n - 1) + b(n - 1) + c(n - 1)) \\   6 \times 2 {}^{n }

<h2>c)</h2>

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