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hichkok12 [17]
2 years ago
12

Can somebody please solve these for me I don't wana do it (thats why i am using so many points)

Mathematics
1 answer:
natta225 [31]2 years ago
4 0

Down                            

6. 4,011                          

10. -94

11. 26

13. 178

15. -8

16. 6,861

18. 3,482

20. 385

22. 788

24. -5

25. 44

Across

1. -248

5. -9

7. 4,923

8. 90

9. 67

10. -912

12. 119

14. 16

15. -6

17. 743

19. 8,838

21. 47

23. 68

24. -884

26. 15

27. 7,284

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I need help with 5 and 14 pls
Julli [10]

Answer:

5

(3a²b³c)³(2a⁴b²c²)³

= (3a⁶b⁹c³)(8a¹²b⁶c⁶)

= 24a¹⁸b¹⁵c⁹

14

⁴√(81a¹⁶b¹²c⁹)

= (⁴√81)(⁴√a¹⁶)(⁴√b¹²)(⁴√c⁹)

= 3 (a^{\frac{16}{4} }) (b^{\frac{12}{4} } ) (c^{\frac{9}{4} } )

= 3a^{4} b^{3} c^{\frac{9}{4} }

4 0
3 years ago
The answer to these please!
igomit [66]
\sqrt[4]{(4a^{2})^{6}} = \sqrt[4]{4096a^{12}} = 8a^{3}

\sqrt[7]{(b^{\frac{5}{3}})^{8}} = \sqrt[7]{b^\frac{40}{3}} = b^{\frac{40}{21}} = \sqrt[21]{b^{40}} = \sqrt[21]{b^{21} * b^{19}} = \sqrt[21]{b^{21}} \sqrt[21]{b^{19}} = b\sqrt[21]{b^{19}}

\sqrt[3]{\frac{c^{9}}{c^{3}}} = \sqrt[3]{c^{6}} = c^{2}

\sqrt[3]{27d^{6} * 8d^{-4}} = \sqrt[3]{27d^{6} * \frac{8}{d^{4}}} = \sqrt[3]{216d^{2}} = 6\sqrt[3]{d^{2}} = 6d^{\frac{2}{3}}
4 0
3 years ago
Read 2 more answers
Worth 20 points, please help!
serg [7]

Answer: 3


Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

1. Find the prime factorization of 27:

27=3*3*3 or 27=3^{3}

2.  The index of the radical is 3, therefore, you have rewrite it as following:

\sqrt[3]{27}=\sqrt[3]{3^{3}}=3^{\frac{3}{3}}=3^{1}=3

3. Therefore, as you can see, the answer is 3.


5 0
3 years ago
A college student completed some courses worth 3 credits and some courses worth 4 credits. The studentearned a total of 59 credi
Korolek [52]

Answer:

<em>The student completed 13 courses worth 3 credits</em>

Step-by-step explanation:

<u>System of Equations</u>

Let's assign the following variables:

x = number of courses worth 3 credits

y = number of courses worth 4 credits

Some student completed 18 courses thus:

x + y = 18      [1]

The student earned a total of 59 credits:

3x + 4y = 59       [2]

From [1]:

y = 18 - x

Substituting in [2]:

3x + 4(18 - x) = 59

Operating:

3x + 72 - 4x = 59

Simplifying:

-x = 59 - 72 = -13

x = 13

The student completed 13 courses worth 3 credits

5 0
2 years ago
10; your car travels for 10 hours.
Assoli18 [71]

The algebraic expression that represents the total distance traveled by the car is 10s

<h3>How to determine the algebraic expression?</h3>

The given parameters are:

  • Speed = s miles per hour
  • Time = 10 hours

The distance is calculated using:

Distance = Speed * Time

So, we have:

Distance = s* 10

Evaluate

Distance = 10s

Hence, the algebraic expression that represents the total distance traveled by the car is 10s

Read more about distance and speed at:

brainly.com/question/4931057

#SPJ1

<u>Complete question</u>

Your car travels for 10 hours at an average speed of s miles per hour. Write an algebraic expression that represents the total distance traveled by the car

5 0
1 year ago
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