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sweet-ann [11.9K]
3 years ago
7

Help urgently please❤️ I’ll mark u brainlyest thank u

Mathematics
1 answer:
ELEN [110]3 years ago
6 0

Answer:

-1/2 and 2

Step-by-step explanation:

Since you need y=mx+b you have to convert your equation to match this

So, 3x+6y=12

Subtract 3x from both sides to get the y term on the left side alone.

This leaves 6y=-3x+12

From there divide 6 from both sides to give you your y term alone on the left side completely.

That leaves you with y=-1/2x+2

Meaning your M=-1/2 and your B=2

Your graph then should have the start point be at y=2 from there move -1 spaces down the y axis, and go to spaces to the right. Making your line move between r and n

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Graph the function f(x)=32x−4. Use the line tool and select two points to graph.
muminat

Answer:

I believe the points (0,-4) and (1,28) work. You can also use (0.125,0) if you can.

4 0
3 years ago
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Anna [14]
Subtract 59 from both sides, you get x=-179
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3 years ago
4-inch by 6-inch what is the width of 15 inches for a ratio table
quester [9]

This is a ratio problem; the ratio of the length to width is constant (and therefore equal):

4 /6 = 15 / x

Now, with a ratio, we may do any allowable algebra operation: cross-multiply, invert both sides, multiply or divide both sides by the same amount, etc.

Let's cross-multiply:

4x = (15)(6)

x = 90/4

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3 0
3 years ago
1. 4x-8+2x+-5x+x²-3=<br> 2.3x+5x=<br> 3.2r+4+3x-2=<br> 4.3x-2y-x+5y=<br> 5.2y²-8y³+5y-5y²+4y³=
Marrrta [24]
1. 4x - 8 + 2x + (-5x) + x^2 - 3 = 4x - 8 + 2x - 5x + x^2 - 3...now, we just combine like terms....lets group them...it will be easier ...x^2 + (4x + 2x - 5x ) - 8 - 3 = x^2 + x - 11

2. 2x + 5x = 8x

3. 2r + 4 + 3x - 2 = 3x + 2r + (4 - 2) = 3x + 2r + 2

4. 3x - 2y - x + 5y = (3x - x) + (5y - 2y) = 2x + 3y

5. 2y^2 - 8y^3 + 5y - 5y^2 + 4y^3 = (4y^3 - 8y^3) + (2y^2 - 5y^2) + 5y =
    -4y^3 - 3y^2 + 5y
3 0
3 years ago
Determine whether each relation is a function. Give the domain and range for each relation.
brilliants [131]

Answer:

Not a function

Domain: {3,4}

Range: {4,5}

Step-by-step explanation:

A function is a relation where each input has its own output. In other words if the x value has multiple corresponding y values then the relation is not a function

For the relation given {(3, 4), (3, 5), (4, 4), (4, 5)} the x value 3 and 4 have more than one corresponding y value therefore the relation shown is not a function

Now let's find the domain and range.

Domain is the set of x values in a relation.

The x values of the given relation are 3 and 4 so the domain is {3,4}

The range is the set of y values in a relation

The y value of the given relation include 4 and 5

So the range would be {4,5}

Notes:

The values of x and y should be written from least to greatest when writing them out as domain and range.

They should be written inside of brackets

Do not repeat numbers when writing the domain and range

3 0
3 years ago
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