Find three consecutive integers such that three times the third is the same as 2 les than the sum of the first and second
1 answer:
Let the integers be x, x+1 and x+2.
Thus, 3(x + 2) = (x + x + 1) - 2
Then 3x + 6 = 2x + 1 - 2, or 3x + 6 = 2x - 1
Solving for x, x = - 7.
First number is -7
Second one is -6
Third one is -5
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