Find three consecutive integers such that three times the third is the same as 2 les than the sum of the first and second

1 answer:

5 0

Let the integers be x, x+1 and x+2.

Thus, 3(x + 2) = (x + x + 1) - 2

Then 3x + 6 = 2x + 1 - 2, or 3x + 6 = 2x - 1

Solving for x, x = - 7.

First number is -7
Second one is -6
Third one is -5

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