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Anton [14]
4 years ago
5

Which is the best way to choose a random sample of people from a sold-out movie audience for a survey?

Mathematics
1 answer:
EastWind [94]4 years ago
3 0
The best way is to completely randomize the people you pick, and get a large array of diverse people. People of different ages, sizes, living in different places. You can do this by gathering all of the people’s phone numbers, randomizing them, then calling quite a few. Make sure you get many people. This way, it will be unbiased.

Hope this helps! Comment if you have any questions or concerns! :)
You might be interested in
Please help !! <br><br> 25 points !!!
EastWind [94]

Answer:

30

Step-by-step explanation:

70-40=30

8 0
3 years ago
What is the number of terms in this geometric series?<br> 1+2+4...+128
Stella [2.4K]
The answer is : a^2=1 x 2^n-1

To check if it’s correct

a^2= 1 x 2^2-1

a^2 = 1x 2
a^2 = 2

Hope this helps!



5 0
3 years ago
Which expression uses the associative property to make it easier to evaluate 8(1\2 · 1\3)? HELP PLZZZZ ​
Usimov [2.4K]

Answer:

(8x1/2)1/3

Step-by-step explanation:

i took the quiz

5 0
3 years ago
1 2 3 4 5 6 7 8 10 Which set of steps will translate f(x) = 67 to g(x) = 67-5-7? Shift f(x) = 6X five units to the left and seve
True [87]

Answer:

Shift f(x) = 6' seven units to the left and five units down.

Step-by-step explanation:

6 0
3 years ago
Plastic Knives are sold in packs of 18 for 45p. Plastic Forks are sold in packs of 15 for 41p. Jace wants to buy the same number
Flauer [41]

Answer:

430p

Step-by-step explanation:

For this, we'll find the least common multiple for 15 and 18.

=> The least common multiple for 15 and 18 is 90

<u><em>Plastic Knives:</em></u>

Jace will buy 90 knives.  

=> Packets = 90/18 = 5 Packets

Money for 5 Packets = 5 * 45

=> 225p

<u><em>Plastic Forks:</em></u>

Jace will buy 90 forks also.

=> Packets = 90/15 = 6 Packets

Money fro 6 packets = 6 * 41

=> 205p

<u><em>Least Amount of Money Jace will spend</em></u> = 225p+205p

=> 430p

6 0
4 years ago
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