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musickatia [10]
2 years ago
13

Need to know this now pls !!! NEED THE PROCESS , TOO!!! x squared - 18x = -117

Mathematics
2 answers:
Sergeu [11.5K]2 years ago
6 0

Answer:

x_1=9+6i

x_2=9-6i

Step-by-step explanation:

<u>Given:</u>

x^2-18x=-117

<u>Rewrite as a quadratic equation:</u>

x^2-18x+117=0

<u>Use the quadratic formula:</u>

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-(-18)\pm\sqrt{(-18)^2-4(1)(117)}}{2(1)}

x=\frac{18\pm\sqrt{324-468}}{2}

x=\frac{18\pm\sqrt{-144}}{2} <-- No real solutions since discriminant is negative

<u>Continuation:</u>

x=\frac{18\pm\sqrt{-1*144}}{2}

x=\frac{18\pm\sqrt{-1}\sqrt{144}}{2}

x=\frac{18\pm12i}{2} <-- Recall that \sqrt{-1}=i

x=9\pm6i

<u>Solutions:</u>

x_1=9+6i

x_2=9-6i

nydimaria [60]2 years ago
3 0

Answer:

x = 9 + 6i or x = 9 - 6i

Step-by-step explanation:

x² - 18x + 117 = 0

Complete the square and solve:

(x - 9)² - 81 + 117 = 0

(x - 9)² + 36 = 0

(x - 9)² = -36

x - 9 = ±sqrt(-36)

x - 9 = ±sqrt(-1).sqrt(36)

i = imaginary number = sqrt(-1)

x - 9 = ±6i

x = 9 ± 6i

There are no real solutions, only imaginary ones

9 + 6i and 9 - 6i

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3 years ago
In rectangle DATE, the diagonals DT and AE intersect as S. If LaTeX: AE=40 A E = 40 and LaTeX: ST=x+5 S T = x + 5 , find the val
svetoff [14.1K]
For this case we have the following diagonals:
 AE = 40
 ST = x + 5
 The intersection of the diagonals occurs when:
 AE = ST
 Therefore, matching we have:
 40 = x + 5
 Clearing x we have:
 x = 40-5
 x = 35
 Answer:
 The value of x is:
 x = 35
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