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musickatia [10]
2 years ago
13

Need to know this now pls !!! NEED THE PROCESS , TOO!!! x squared - 18x = -117

Mathematics
2 answers:
Sergeu [11.5K]2 years ago
6 0

Answer:

x_1=9+6i

x_2=9-6i

Step-by-step explanation:

<u>Given:</u>

x^2-18x=-117

<u>Rewrite as a quadratic equation:</u>

x^2-18x+117=0

<u>Use the quadratic formula:</u>

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-(-18)\pm\sqrt{(-18)^2-4(1)(117)}}{2(1)}

x=\frac{18\pm\sqrt{324-468}}{2}

x=\frac{18\pm\sqrt{-144}}{2} <-- No real solutions since discriminant is negative

<u>Continuation:</u>

x=\frac{18\pm\sqrt{-1*144}}{2}

x=\frac{18\pm\sqrt{-1}\sqrt{144}}{2}

x=\frac{18\pm12i}{2} <-- Recall that \sqrt{-1}=i

x=9\pm6i

<u>Solutions:</u>

x_1=9+6i

x_2=9-6i

nydimaria [60]2 years ago
3 0

Answer:

x = 9 + 6i or x = 9 - 6i

Step-by-step explanation:

x² - 18x + 117 = 0

Complete the square and solve:

(x - 9)² - 81 + 117 = 0

(x - 9)² + 36 = 0

(x - 9)² = -36

x - 9 = ±sqrt(-36)

x - 9 = ±sqrt(-1).sqrt(36)

i = imaginary number = sqrt(-1)

x - 9 = ±6i

x = 9 ± 6i

There are no real solutions, only imaginary ones

9 + 6i and 9 - 6i

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Zepler [3.9K]

1. - 4 = \frac{x}{9}

=> x = - 36

___________

2. -18 = 6t

=> t = \frac{-18}{6}

=> t = -3

___________

3. x - 18 = -72

=> x = - 72 + 18

=> x = - 54

___________

4. -18 = x - 15

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7 0
2 years ago
(2, -4), (x, y) , A , and B all lie on the line. Find an equation relating x and y.​
frutty [35]

Answer:

An equation relating x and y is:

y = 3/4x - 5.5

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

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  • b is the y-intercept

Given the points

(2, -4), (x, y), A(6, -1), and B(10, 2)

Taking any two points let say A(6, -1), and B(10, 2) to determine the slope

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(6,\:-1\right),\:\left(x_2,\:y_2\right)=\left(10,\:2\right)

m=\frac{2-\left(-1\right)}{10-6}

Refine

m=\frac{3}{4}

We know that the value of the y-intercept can be determined by setting x = 0, and determining the corresponding value of y.

From the graph, it is clear

at x = 0, y = -5.5

Thus, the y-intercept b = -5.5

Thus, substituting b = -5.5 and m = 3/4 in the slope-intercept form of the line equation

y = mx+b

y = 3/4x + (-5.5)

y = 3/4x - 5.5

Therefore, an equation relating x and y is:

y = 3/4x - 5.5

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Is there more to problem or is this it?


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Verify and show work<br><br> csc x - cos x • cot x = sin x
Vladimir79 [104]

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Step-by-step explanation:

∵ sinx + (cotx)(cosx) = √3

∵ sinx + (cosx/sinx)(cosx) = √3

∴ sinx + cos²x/sinx = √3

∵ cos²x = 1 - sin²x

∴ sinx + (1 - sin²x)/sinx = √3 ⇒ make L.C.M

∴ (sin²x + 1 - sin²x)/sinx = √3

∴ 1/sinx = √3

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