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Lena [83]
2 years ago
14

Savannah has an action figure collection. She keeps 57 of the action figures on her wall, which is 19% of her entire collection.

What is the total number of action figures in Savannah's collection?
Mathematics
1 answer:
beks73 [17]2 years ago
5 0

Answer:

She has a total of 300 action figures.

Step-by-step explanation:

19 : 100 = 57 : x

x = 100/19 * 57

x = 300

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If 12x + 3 - 4x - 3 = 8, then x = ?
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8x = 8
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7 ^ 8 times 7 ^ 3 times 7 ^ 4 / 7 ^ 9 times 7 ^ 5​
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7^8 =5764801 * 7^3 =343 * 7^4 =2401 ÷ 7^9 = 40353607 * 7^5 =16807

5764801 *343 *2401 ÷ 40353607 *16807

=4747561509943 ÷ 678223072849 = 7

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A sales girl earns a basic salary of shs.
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2 years ago
2x² + 4x + 4 + x² + 1 = 180
Tasya [4]

Step-by-step explanation:

2 {x}^{2}  + 4x + 4 +  {x}^{2}  + 1 = 180

3 {x}^{2}  + 4x + 5 = 180

{3x}^{2}  + 25x - 21x - 175 = 0

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(3x + 25) \times (x - 7) = 0

3x + 25 = 0 = x - 7 = 0

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5 0
2 years ago
The least common multiple of two numbers is 3780, and the greatest common divisor is 18. given that one of the numbers is 180, w
garri49 [273]
<span>To solve these GCF and LCM problems, factor the numbers you're working with into primes: 
3780 = 2*2*3*3*3*5*7
180 = 2*2*3*3*5 
</span><span>We know that the LCM of the two numbers, call them A and B, = 3780 and that A = 180. The greatest common factor of 180 and B = 18 so B has factors 2*3*3 in common with 180 but no other factors in common with 180. So, B has no more 2's and no 5's
</span><span>Now, LCM(180,B) = 3780. So, A or B must have each of the factors of 3780. B needs another factor of 3 and a factor of 7 since LCM(A,B) needs for either A or B to have a factor of 2*2, which A has, and a factor of 3*3*3, which B will have with another factor of 3, and a factor of 7, which B will have. 
So, B = 2*3*3*3*7 = 378.</span>
8 0
2 years ago
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