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Sonbull [250]
3 years ago
15

Keri is making a doll clothes for a holiday craft show. The wholesale cost of the materials for one outfit is $9.38. If she sell

s an outfit for $15, what is the nearest percent?
Mathematics
1 answer:
irinina [24]3 years ago
5 0

Answer:

60%

Step-by-step explanation:

If I get you right, you're asking for the percentage gain to the nearest percentage, right?

Now to do this, we need to get the amount of profit she made. That's quite easy, we only need to subtract the cost price from the selling price. And that equals $15 - $9.38 that equals $5.62.

Now, we divide this value by the cost price and multiply by 100% to get the percentage gain.

I.e 5.62/9.38 × 100%.

That gives 59.9% , which equals 60% when approximated to the nearest percentage.

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17,254 to the nearest 1000
amm1812

17,254 to the nearest 1000


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3 years ago
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Henry's wage is £450 per week.
marishachu [46]

Answer:

He saves £135 each week

Step-by-step explanation:

He spends 2/5 of his wage on food

2/5x450=£180

He spends 180£ on food each week

30% of 450 is 135 which he spends on house holdbills. thus, he pays £135 on bills

so his total expenditure is 135+180= £315

he saves the rest which is £135.

thus, your answer is £135

4 0
3 years ago
Easy math please help i'll mark brainliest
katen-ka-za [31]

Answer:

D, D, A, C

Step-by-step explanation:

Congruent means equal.

T and r are alternate angles

Vertically opposite angles are equal

Y is 47 degrees because since the full angle is 90 degrees, subtract:

90-43 = 47

Hope this helps :)

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3 years ago
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Line p passes through A(-2, -4) and has a slope of -1/2. What is the standard form of the equation for line p?
ValentinkaMS [17]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
For what value of k is there one solution to the given quadratic equation (k+1)x²+4kx+2=0.
andriy [413]

Answer:

If k = 1 or k = -\frac{1}{2}, there is only one solution to the given quadratic equation.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = (x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

The signal of \bigtriangleup determines how many real roots an equation has:

\bigtriangleup > 0: Two real and different solutions

\bigtriangleup = 0: One real solution

\bigtriangleup < 0: No real solutions

In this problem, we have the following second order polynomial:

(k+1)x^{2} + 4kx + 2 = 0.

This means that a = k+1; b = 4k; c = 2

It has one solution if

\bigtriangleup = 0

b^{2} - 4ac = 0

16k^{2} -8(k+1) = 0

16k^{2} - 8k - 8 = 0

We can simplify by 8

2k^{2} - k - 1 = 0

The solution is:

k = 1 or k = -\frac{1}{2}

So, if k = 1 or k = -\frac{1}{2}, there is only one solution to the given quadratic equation.

4 0
3 years ago
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