Ask question

Ask question

All categories

3 years ago

8

Adam was going to sell all of his stamp collection to buy a video game. After selling half of them he changed his mind and did n

ot sell the rest. He then bought ten more, How many did he start with if he now has 31?

1 answer:

Roman55 [17]3 years ago

6 0

He would have 21 before he bought the 10 stamp because 31-10=21

You might be interested in

I need help on this ASAP no fofo answers

melomori [17]

(hope this helps)

FINAL ANSWER:

(B) Equation of y =5x

EXPLANATION:

Not a complete representation due to the fact that it only shows students counting by 5. It can be used to create and equation of
Y= 5x because for every x, the y is 5 times more.

EX: 5 students. 5x5= $25. X=5 Y=25

4 0

3 years ago

3x+2=0 i need the answer quick

Alinara [238K]

Answer:

$\huge\boxed{\sf x = -2/3}$

Step-by-step explanation:

<h3><u>Given equation:</u></h3>

3x + 2 = 0

Subtract 2 to both sides

3x = 0 - 2

3x = -2

Divide 3 to both sides

x = -2/3

$\rule[225]{225}{2}$

6 0

2 years ago

Please help me answer

pishuonlain [190]

1. given
2. transitive prop of equality
3. subtraction property of equality<span />

6 0

3 years ago

Three forces act on a hook. Determine the magnitude of the resultant of the force.

Novay_Z [31]

Use Hooke's law... (just kidding)

Break down each force vector into horizontal and vertical components.

$\vec F_1=(1000\,\mathrm N)(\cos30^\circ\,\vec x+\sin30^\circ\,\vec y)\approx(866.025\,\mathrm N)\,\vec x+(500\,\mathrm N)\,\vec y$

$\vec F_2=(1500\,\mathrm N)(\cos160^\circ\,\vec x+\sin160^\circ\,\vec y)\approx(-1409.54\,\mathrm N)\,\vec x+(513.03\,\mathrm N)\,\vec y$

$\vec F_3=(750\,\mathrm N)(\cos195^\circ\,\vec x+\sin195^\circ\,\vec y)\approx(-724.444\,\mathrm N)\,\vec x+(-194.114\,\mathrm N)\,\vec y$

The resultant force is the sum of these vectors,

$\vec F=\displaystyle\sum_{i=1}^3\vec F_i\approx(-1267.96\,\mathrm N)\,\vec x+(818.916\,\mathrm N)\,\vec y$

and has magnitude

$|\vec F|\approx\sqrt{(-1267.96\,\mathrm N)^2+(818.916\,\mathrm N)^2}\approx1509.42\,\mathrm N$

The closest answer is D.

5 0

3 years ago

Find the missing side.<br> Round to the nearest tenth.<br> For all 4 pics

Firlakuza [10]

Answer:

1st pic) 17.8

2nd pic) 16.8

3rd pic) 9.1

4th pic) 13.5

Step-by-step explanation:

<u>1st pic:</u> $cos = \frac{adjacent}{hypothenuse}$

(write equation) Cos 27 (cos 27 = 0.89) = $\frac{x}{20}$

(new equation) 0. 89 = $\frac{x}{20}$

(multiply 20 on both sides) 0.89 x 20 = $\frac{x}{20}$ x 20

(solve) 17.8 = x

<u>2nd pic:</u> $tan = \frac{adjacentx}{hypothenuse}$

(write equation) tan 40 (tan 40 = 0.84) = $\frac{32}{x}$

(new equation) 0.84 = $\frac{32}{x}$

(multiply 32 on both sides) 0.84 x 20 = $\frac{32}{x}$ x 20

(solve) 16.8 = x

<u>3rd pic:</u> $cos = \frac{adjacent}{hypothenuse}$

(write equation) cos 55 (cos 55 = 0.57) = $\frac{16}{x}$

(new equation) 0.57 = $\frac{16}{x}$

(multiply 16 on both sides) 0.57 x 16 = $\frac{16}{x}$ x 16

(solve) 9.1 = x

<u>4th pic:</u> $tan = \frac{adjacentx}{hypothenuse}$

(write eqaution) tan 42 (tan 42 = 0.90) = $\frac{x}{15}$

(new equation) 0.90 = $\frac{x}{15}$

(multiply 15 on both sides) 0.90 x 15 = $\frac{x}{15}$ x 15

(solve) 13.5 = x

4 0

3 years ago