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PSYCHO15rus [73]

3 years ago

15

PLEASE PLEASE HELP I WILL MARK THE BRAINLIEST!!!!!

1 answer:

Free_Kalibri [48]3 years ago

8 0

Answer:

<u>The average cost of a cat's annual visit is about <em>$23.71 less</em> at A New Leash on Life Animal Clinic than the average cost for a cat's annual visit at No Ruff Stuff Animal </u><u>Hospital.</u>

Explanation:

As you can see from the data and graph given, the Mean is essentially the average cost and $101.13 (New Leash on Life) is $23.71 less than $121.84 (No Ruff Stuff Animal Hospital).

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Nikolas calculated the volume of the prism. His work is shown below. A triangular prism. The triangular base has a base of 5.8 f

Brut [27]

Answer:

B he used the incorrect formula for the volume of the prism

3 0

3 years ago

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I need help with this!!!

7nadin3 [17]

Answer:

6

Step-by-step explanation:

cancel out 5 by multiplying its by 5, what you do to one side you do to the other. so you also multiply 12 by 5. and you should get 60

3 0

3 years ago

You invest $3000 in an account at 3.5% per year simple interest. How much will

Schach [20]

Answer:

Option "D" is correct $3630

Step-by-step explanation:

At the beginning of the 7th year, the money has been in the account for 6 years.

The simple interest on $3000 at 3.5% for 6 years is I = prt:

(3000) = (.035) = (6) = 360

he amount in the account at the <u>beginning of the 7th year</u> is then the <u>original amount plus</u> the interest <u>$3630.</u>

3 0

2 years ago

(−5k<br> 3<br> −6k+1)+(−6k<br> 2<br> +5k)

Fittoniya [83]

Remove unnecessary parenthesis.

-5k 3 - 6k +1 - 6k 2 + 5k (simplify each term) -15k - 6k + 1 - 12k +5k = -28k +1

Answer: 28k + 1

7 0

3 years ago

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Total profit P is the difference between total revenue R and total cost C. Given the following total-revenue and total-cost fu

gavmur [86]

Answer:

The profit function is:

$P(x)=-x^2+1280x-3300$

The maximum value is 406, 300 occurring when x = 640.

Step-by-step explanation:

The revenue function is:

$R(x)=1300x-x^2$

And the cost function is:

$C(x)=3300+20x$

Then the total profit function will be:

$P(x)=R(x)-C(x)=(1300x-x^2)-(3300+20x)=-x^2+1280x-3300$

This is a quadratic function.

Therefore, the maximum value of the total profit will occur at its vertex point.

The vertex of a quadratic is given by:

$\displaystyle \Big(-\frac{b}{2a}, f\Big(-\frac{b}{2a}\Big)\Big)$

In this case, a = -1, b = 1280, and c = -3300.

Then the point at which the maximum profit occurs is at:

$\displaystyle x=-\frac{1280}{2(-1)}=640$

And the maximum profit will be:

$P(640)=-(640)^2+1280(640)-3300=406300$

5 0

3 years ago

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