2/3y-2/5=5
We move all terms to the left:
2/3y-2/5-(5)=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
determiningTheFunctionDomain
2/3y-5-2/5=0
We calculate fractions
There is no solution for this equation
Let the number of $1 bill be x and $5 bill be y
x=5y
5y+y=48
6y=48
x=40
y=8
number of $1 bill= 40
number of $5 bill = 8
You can resolve all of them.
so the first one would be 3q+2p
that second 2p+3q
the third 2p+2q+q which equals 2p+3q
they all end up as the same thing so both are equivalent
It has a minimum value at x = 3 and f(x) = 4
Vertex form is
f(x) = a(x - 3)^2 + 4 where a is some constant to be found
From the graph when x = 5 f(x) = 15, so
15 = a * 2^2 + 4
a = 15-4/4 = 11/4
so our equation is f(x) = 11/4(x - 3)^2 + 4
