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Gemiola [76]
3 years ago
8

How many real solutions does this system of equations have? (x−3)^2+(y+1)^2=16x−7=0

Mathematics
2 answers:
Alinara [238K]3 years ago
6 0

Answer:

infinitely many

Step-by-step explanation:

Modeling with Systems assignment edge 2021:)

romanna [79]3 years ago
4 0

Answer:

Unsolvable

Step-by-step explanation:

This system right here has no solutions, maybe try something else if you were looking for a problem with multiple answers.

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the interest on an investment varies directly as the rate of of interest. if interest is $47 when interst rate is 5% find the in
NNADVOKAT [17]

Answer:

The interest when rate is 5.2% is $48.88

Step-by-step explanation:

if interest (I) varies directly as interest rate (R)

Then

I ∝ R

I=cR

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if interest is $47 when interest rate is 5%

47 =.05c

c = 940

if interest rate is 5.2% then

I = 940 x .052

=48.88

=$48.88

7 0
3 years ago
A caterer has 5 rolls. He is ordering more rolls. He can order up to 9 packages of rolls and each package contains 12 rolls. The
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B is the practical domain of the function

6 0
3 years ago
A rectangular swimming pool measures 50 meters in length and 25 meters in width. What are the length and width of your scaled dr
morpeh [17]

Answer:

10 cm by 5cm

Step-by-step explanation:

We know that for every 5 meters, there will be 1 centimeter. The pool is 50 meters by 25 meters. So to find this in terms of centimters, divide by 5 to get 10 cm by 5 cm.

7 0
4 years ago
Roger can run one mile in 8 minutes. jeff can run one mile in 6 minutes. if jeff gives roger a 1 minute head​ start, how long wi
Anastasy [175]
Recall your d = rt, distance = rate * time.

now, if Roger can do 1 mile in 8 minutes, so in 1 minute, he has done then 1/8 of a mile, so his rate is 1/8 miles per minute.

if Jeff can do 1 mile in 6 minutes, he's faster, in 1 minute he has done 1/6 of a mile, so his rate is 1/6 miles per minute.

now, when Jeff catches up with Roger, the distance covered by both will be the same, say "d" miles, because, at that millisecond, Jeff will be neck and neck with Roger, and their covered distance will be the same.

now, Jeff is generous and let Roger roll on for 1 minute before him, so, by the time time Roger has covered "d" miles, he has been running for say "t" minutes.

however, since Jeff started later by 1 minute, he hasn't been running for "t" minutes, but for "t - 1" minutes.

\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mpm}{rate}&\stackrel{minutes}{time}\\
&------&------&------\\
Roger&d&\frac{1}{8}&t\\\\
Jeff&d&\frac{1}{6}&t-1
\end{array}
\\\\\\
\begin{cases}
\boxed{d}=\frac{1}{8}t\\\\
d=\frac{1}{6}(t-1)\\
------\\
\boxed{\frac{1}{8}t}=\cfrac{t-1}{6}
\end{cases}
\\\\\\
\cfrac{t}{8}=\cfrac{t-1}{6}\implies 6t=8t-8\implies 8=2t\implies \cfrac{8}{2}=t\implies \boxed{\stackrel{mins}{4}=t}
4 0
3 years ago
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