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dimulka [17.4K]
3 years ago
5

There are 11 women and 9 men in a certain club. If the club is to select a committee of 2 women and 2 men, how many different su

ch committees are possible?
Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0
We can tell it’s not a permutation because it’s picking two people. Order doesn’t matter.

The number of total possible groups of men is 9 C 2 = 9!/((9-2)!(2!)) = 36

The number of total possible groups of women is 11 C 2 = 11!/((11-2)!(2!)) = 55

55 * 36 = 1980 different groups in the committee
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Answer:

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* Lets revise the trigonometry transformation

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