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Mazyrski [523]
3 years ago
12

Solve. Show all your work. a) -3x+2 = 5 b) }(4x – 4) = 7 Help help help please

Mathematics
2 answers:
Doss [256]3 years ago
6 0
A) x = -1
b) x = 11 / 4

a explanation)
-3 x + 2 = 5
-3 x + 2 - 2 = 5 - 2
-3 x = 5 - 2
-3 x = 3
-3 x / -3 = 3 / -3
x = 3 / -3
x = -1

b explanation)
4 x - 4 = 7
4 x - 4 + 4 = 7 + 4
4 x = 7 + 4
4 x = 11
4 x / 4 = 11 / 4
x = 11 / 4
Reptile [31]3 years ago
3 0

Answer:

A) x=-1

B) x=11/4

Step-by-step explanation:

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Step-by-step explanation:

6 0
3 years ago
What is 25 2/3 - 15 1/3 =
Ira Lisetskai [31]

Answer:

10 1/3

Step-by-step explanation:

Convert mixed numbers into improper fractions (whole number × denominator + numerator)

25 2/3 and 15 1/3

25 × 3 + 2 = 75 + 2 = 77

Put the number over the same denominator

77/3

15 × 3 + 1 = 45 + 1 = 46

Put the number over the same denominator

46/3

77/3 - 46/3

They have common denominators so we can simply subtract the numerator values

77 - 46/3

31/3

To convert it back to a whole number, find how many times 3 fits into 31 evenly

It fits 10 times evenly with 1 remainding which looks like:

10 1/3

7 0
3 years ago
Find the components of the vertical force Bold Upper Fequalsleft angle 0 comma negative 8 right anglein the directions parallel
nydimaria [60]

Answer with Step-by-step explanation:

We are given that

F=<0,-8>=0i-8j=-8j

\theta=\frac{\pi}{3}

The component of force is divided into two direction

1.Along the plane

2.Perpendicular to the plane

1.The vector parallel to the plane will be=r=cos\frac{\pi}{3}i-sin\frac{\pi}{3}j=\frac{1}{2}i-\frac{\sqrt 3}{2}j

By using cos\frac{\pi}{3}=\frac{1}{2},sin\frac{\pi}{3}=\frac{\sqrt 3}{2}

Force along the plane will be=\mid F_x\mid=F\cdot r

Force along the plane will be =\mid F_x\mid=F\cdot (\frac{1}{2}i-\frac{\sqrt 3}{2}j)=-8j\cdot(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=8\times \frac{\sqrt 3}{2}=4\sqrt 3N

By using i\cdot i=j\cdoty j=k\cdot k=1,i\cdot j=j\cdot k=k\cdot i=j\cdot i=k\cdot j=i\cdot k=0

Therefore, force along the plane=\mid F_x\mid(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)

2.The vector perpendicular to the plane=r=-sin\frac{\pi}{3}-cos\frac{\pi}{3}=-\frac{\sqrt 3}{2}i-\frac{1}{2}j

The force perpendicular to the plane=\mid F_y\mid=F\cdot r=-8j(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

The force perpendicular to the plane=4N

Therefore, F_y=4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

Sum of two component of force=F_x+F_y=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)+4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

Sum of two component of force=2\sqrt 3i-6j-2\sqrt3 i-2j=-8j

Hence,sum of two component of forces=Total force.

6 0
3 years ago
The old price of a 24" television is $499.00. It has been marked up 12%. What is the new price?
BartSMP [9]

Answer:

$558.88

Step-by-step explanation:

6 0
3 years ago
Write an expression for the area of square 5 by combining the areas of the four triangles and the one square.
Alekssandra [29.7K]

Answer:

2ab + c²

Step-by-step explanation:

Please find attached a diagram of square 5

Area of a triangle = 1/2 x ( base x height)

(1/2 x (a xb) ) x 4 = 2ab

The Pythagoras theorem : a² + b² = c²

where a = length

b = base

c =  hypotenuse

a² + b² = c²

a² + 2ab+ b² = 2ab + c²

5 0
3 years ago
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