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Helen [10]
3 years ago
14

Gina Chuez has considered starting her own custom greeting card business. With an initial start up cost of $1500, she figures it

will cost $0.45 to produce each card. In order to remain competitive with the larger greeting card companies, Gina must sell her cards for no more than $1.70 each. To make a profit, her income must exceed her costs. How many cards must she sell before making a profit?
A. 1187 B. 1230 C.1200 D.1425
Mathematics
1 answer:
Digiron [165]3 years ago
6 0

1.70 - 0.45 = 1.25

1500 ÷ 1.25 = 1200

Gina must sell 1200 cards before she can make a profit

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The ellipse x^2/4 + y^2/16 = 1<br> Has a vertical axis of??<br> 8<br> 16<br> 4<br> 3
photoshop1234 [79]
I might be wrong but I say 16
8 0
3 years ago
There are 4 people at a party. Consider the random variable X=’number of people having the same birthday ’ (match only month, N=
yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = \frac{12P4}{12^{4} }

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = \frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }

P(X=2) = 0.401

P(X=3) = \frac{4C3 * 12P2}{12^{4} }

P(x=3) = 0.025

P(X=4) = \frac{12}{12^{4} }

P(X=4) = 0.001

Mean, \mu = \sum xP(x)

\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879

Standard deviation, SD = \sqrt{\sum x^{2} P(x) - \mu^{2}}  \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2}  * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}

SD = 1.033

4 0
4 years ago
(x-6)² + (x + 5)² = 16
Phoenix [80]

Answer:

answer A   : (2 -5)

Step-by-step explanation:

the midipoint P,Q is the center A of this circle (because PQ is a diameter)

use : (x-6)²+(x+5)² = 16 you have : A(6 , -5) now  let Q(x,y) :

 (x+10)/2 = 6

    (y-5)/2 = - 5                          

x+10 = 12

y-5 = -10

so : x = 2 and y = - 5....answer A   : (2 -5)

6 0
3 years ago
Help me on this quiz
kolezko [41]

The Answer For Number Two Is Negative 14

7 0
3 years ago
Please help me fast and show all your work please thx ​
MrMuchimi
7x4x5= 140
Hope this helps!
7 0
3 years ago
Read 2 more answers
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