Use the quadratic formula, x=

(don't know how to type the "-"sign in the formula, so there is only the "+" in the formula)
in this case, a=1, c=34, b is unknown
from the roots, we can tell that -b+

=2(5+3i)=10+6i
Note: the original equation already give b as -b, so -(-b)=10, b=10
using b^2-4ac=(6I)^2,
b^2-4*34=-36
b^2=100
you will also get b=10
Answer:
Step-by-step explanation:
1. y = 2x
y = 2*4 = 8 Checks, therefore
y = 20 for x = 10
2. y = 3x
y = 3*(0.3) = 0.9 Checks, therefore:
y = 3*(1.5) = 4.5
y = 3*
3. y = 5/x
y = 5/(1/2) = 10 Checks, therefore:
3 = 5/x
x = 5/3
4 v = wu
7*3 = 21 Checks, therefore:
v = (3/4)*(6) = (18/4) = (9/2)
v = (2/3)wu
v = (2/3)*7*3 = 14 Checks
5 m = Kn/p [Add the K as a constant that will make m = Knp true at some value of K]
9 = K*2/(1/3)
27 = (K*2)
27 = 2K
K = (3/2)
m = (3/2) (n/p)
m = (3/2)*((1/2)/(1/3))
m = (3/2)*(3/2)
m = 1
Answer:
87.96yd
Step-by-step explanation:
C=2πr=2·π·14≈87.96459yd
They can show change on how much time passed.