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Anarel [89]
3 years ago
10

How many solutions does this system of equations have? Use either the substitution method or the elimination method. −2x + 4y =

4−2x + 4y = 4 x − 2y = 6x − 2y = 6 exactly one solution no solution infinitely many solutions
Mathematics
1 answer:
Katen [24]3 years ago
7 0
-2x+4y=4 Equation 1
x-2y=6 Equation 2
Solving by substitution method.
Isolate x from equation 2.
x=2y+6 
Substitute value of x in equation 1
-2(2y+6)+4y=4
-4y-12+4y=4
-12=4
-16=0
Which is false. 

Answer: No solution 
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Find each x-value at which f is discontinuous and for each x-value, determine whether f is continuous from the right, or from th
Alexus [3.1K]

Answer:

the function is continuous from the left at x=1 and continuous from the right at x=0

Step-by-step explanation:

a function is continuous from the right , when

when x→a⁺ lim f(x)=f(a)

and from the left when

when x→a⁻ lim f(x)=f(a)

then since the functions presented are continuous , we have to look for discontinuities only when the functions change

for x=0

when x→0⁺ lim f(x)=lim  e^x = e^0 = 1

when x→0⁻ lim f(x)=lim  (x+4) = (0+4) = 4

then since f(0) = e^0=1 , the function is continuous from the right at x=0

for x=1

when x→1⁺ lim f(x)=lim  (8-x) = (8-0) = 8

when x→1⁻ lim f(x)=lim e^x = e^1 = e

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6 0
3 years ago
For f(x) = 5x + 1
drek231 [11]

Answer:

A. f(7) = 5(7) + 1\\\\f(7) = 36

B. f^{-1}(x) = \frac{x - 1}{5}

C. f^{-1}(7) =\frac{6}{5}

D. f(\frac{6}{5}) = 7

Step-by-step explanation:

A. To solve the first part of the problem we must replace x = 7 in the function f(x) = 5x + 1

So:

f(7) = 5(7) + 1\\\\f(7) = 36

B. In part B we must find the inverse function of f(x) = 5x + 1

To find the inverse function do y = f(x)

y = 5x +1

Now clear the variable x.

\frac{y - 1}{5} = x

Replace x with y.

y = \frac{x - 1}{5}

Finally

f^{-1}(x) = \frac{x - 1}{5}

C. Now we take the inverse function found above and replace x = 7

f^{-1}(7) = \frac{7 - 1}{5}\\\\f(7) = \frac{6}{5}

D. Now we substitute x = f(f^{-1}(7)) in the original function.

x = f( f^{-1}(7))\\\\f^{-1}(7) = \frac{6}{5}\\\\ x= f(\frac{6}{5} )\\\\f(\frac{6}{5}) = 5(\frac{6}{5}) + 1\\\\f(\frac{6}{5}) = 7

8 0
4 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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