Top:
x / (x + 1) - 1 / x
= [x^2 - (x +1)] / x(x+1)
= (x^2 - x - 1 ) / x (x+1)
Bottom:
x / (x + 1) + 1 / x
= [x^2 + (x +1)] / x(x+1)
= (x^2 + x + 1 ) / x (x+1)
Now you have:
(x^2 - x - 1 ) / x (x+1)
----------------------------
(x^2 + x + 1 ) / x (x+1)
= (x^2 - x - 1 ) / x (x+1) * x (x+1) / (x^2 + x + 1 )
= (x^2 - x - 1 ) /(x^2 + x + 1 )
Answer:
x^2 - x - 1
---------------------
x^2 + x + 1
Answer:
Obviously only D is true
Note 2 x - 1 < 10 can be rewritten
2 X < 11 and
x < 5.5
So all of the values in the set would have to be less than 5.5
Answer:
3 1/3
Step-by-step explanation:
4/(2 3/4)
4/(6/4)
4÷6/4
4*4/6
20/6
3 2/6 =3 1/3
Answer:
The difference of 6 times x subtracted from 8 is equal to the sum of 4 added to Twice x
