Try this explanation:
1. if to re-write the given function as:

then it is possible to define its range:
2)
![\lim_{x \to+ \infty}[1- \frac{C}{e^x+C}]=1; \\ \lim_{x \to- \infty}[1- \frac{C}{e^x+C}]=0](https://tex.z-dn.net/?f=%20%5Clim_%7Bx%20%5Cto%2B%20%5Cinfty%7D%5B1-%20%5Cfrac%7BC%7D%7Be%5Ex%2BC%7D%5D%3D1%3B%20%20%5C%5C%20%5Clim_%7Bx%20%5Cto-%20%5Cinfty%7D%5B1-%20%5Cfrac%7BC%7D%7Be%5Ex%2BC%7D%5D%3D0)
answer: (0;1)
Answer:
.......
Step-by-step explanation:
<em>whaaat</em><em>?</em><em> </em>
<em>ok</em><em> </em><em>cool</em><em> </em><em>bye</em><em> </em>
Answer:
60
Step-by-step explanation:
90/100 = 54
Cross multiplying:
100 * 54 / 90
5400/90
60
Answer: I think it' s A, possibly
Answer:
139, I am sorry if I'm wrong
Step-by-step explanation:
a1=11; d=19-11=8
a17=11+(17-1)*8=11+128=139