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AURORKA [14]
3 years ago
12

Jane has just begun her new job as on the sales force of a very competitive company. In a sample of 16 sales calls it was found

that she closed the contract for an average value of 108 dollars with a standard deviation of 12 dollars. Company policy requires that new members of the sales force must exceed an average of more than $100 per contract during the trial employment period. Can we conclude that Jane has met this requirement at the significance level of 90%
Mathematics
1 answer:
mina [271]3 years ago
7 0

Answer:

There is significant evidence that Jane has met the requirement.

Step-by-step explanation:

Given that:

μ = 100

μ > 100

Sample size, n = 16

Sample mean, x = 108

Sample standard deviation, s = 12

Level of significance, α = 0.1

Degree of freedom, df = n - 1 = 16 - 1 = 15

Test statistic

T = (x - μ) / s÷sqrt(n)

Tstatistic = (108 - 100) / 12 ÷ sqrt(16)

Tstatistic = 8 / 3

Tstatistic = 2.6667

Using the pvalue calculator :

Tstatistic at 0.1, df = 15 ;

P-value = 0.008799

Since pvalue < α

We reject the Null

The is no significant evidence to conclude that Jane has exceeded an average of more than $100

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Step-by-step explanation:

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2 years ago
A group consists of fivefive men and fivefive women. ThreeThree people are selected to attend a conference. a. In how many ways
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(10 · 9 · 8) = <em>720 ways</em>.

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b).  Three women can be selected from a group of five women in

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(But every group of 3 different women can be selected in 6 different ways.  So there are actually only (60/6) = 10 different groups of 3 different women.)

   

c).  Start with 3 men and 3 women.

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Then there are 3 men and 2 women.

The probability of the 2nd selection being a woman is (2/5) = 40% .

Then there are 3 men and 1 woman.

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8 0
3 years ago
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Answer:

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Step-by-step explanation:

I assume you mean \frac{9\sqrt{10} }{9\sqrt{11} }

there is a common factor of 9 in the numerator and denominator so we can cancel out to form \frac{\sqrt{10} }{\sqrt{11} }

\frac{\sqrt{10} }{\sqrt{11} } is technically a correct answer, but I will go ahead to rationalize the denominator

multiply \frac{\sqrt{10} }{\sqrt{11} } by some form of 1. this case, we will use \frac{\sqrt{11} }{\sqrt{11} } as our 1.

\frac{\sqrt{10} }{\sqrt{11} }*\frac{\sqrt{11} }{\sqrt{11} } = \frac{\sqrt{10} *\sqrt{11} }{\sqrt{11} *\sqrt{11} } = \frac{\sqrt{110} }{11}

8 0
3 years ago
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