Y = t*e^(-t/2)
y' = t' [e^(-t/2)] + t [e^(-t/2)]' = e^(-t/2) + t[e^(-t/2)][-1/2]=
y' = [e^(-t/2)] [1 - t/2] = (1/2)[e^(-t/2)] [2 - t] = - (1/2) [e^-t/2)] [t -2]
Answer:
The value of x is equal to -2/3.
Step-by-step explanation:
In the problem it says that y equals 2x, and that 3x - 3y = 2.
The first step is to substitute 2x into y.
3x - 3(2x) = 2.
The next step is to use distributive property.
-3(2x) = -6x.
Now we need to add like terms.
3x - 6x = -3x.
Which gives us the equation -3x = 2.
The final step is to divide on both sides to get the value of x.
-3x/-3 = 2/-3.
x = -2/3.
So as you can see, x is equal to -2/3.
We can also check to make sure by redoing the problem, but substituting the value of x.
3(-2/3) - 3(2 * -2/3) = 2.
-2 - 3 * -4/3 = 2.
-2 + 4 = 2.
2 = 2.
The value of x is indeed -2/3.
Yeah you did it right but good job!
Answer:
£10.80
Step-by-step explanation:
20% = 
= 0.2 , then
£54 × 0.2 = £10.80
Answer:
see photo attached
Step-by-step explanation:
edmentum/plato
