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Nitella [24]
3 years ago
5

Which

Mathematics
1 answer:
garik1379 [7]3 years ago
3 0
B.

Because when doing the math, letter B fits the criteria of a quadratic equation. Which is ax^2 + bx + c = 0.

A is wrong because if we were to do the math, there would be no ax^2. The most important thing in a quadratic equation is the term ax^2, bx and c do not matter as much.

C is wrong because there cannot be a greater exponent than ^2.

D is wrong because of the same reason as letter a.
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A ladder 16 feet long is leaning against the wall of a tall building. The base of the ladder is moving away from the wall at a r
svet-max [94.6K]

Answer:

a. 0.588

b. 0.0722

c. 4.576 sqft/sec

Step-by-step explanation:

Let b and h denote the base and height as indicated in the diagram. By pythagoras theorem, h^2 + b^2 = 16^2 = 256 \dotsc\;(1) because it is a right angle triangle.

It is given that \frac{db}{dt} = 1

Now differentiate (1) with respect to t (time) :

\displaystyle{2h\frac{dh}{dt} + 2b\frac{db}{dt} = 0 \implies \frac{dh}{dt} = -\frac{b}{h} \frac{db}{dt}}

\displaystyle{=-\frac{b}{\sqrt{256 - b^2}} \frac{db}{dt} = -\frac{8}{13.856} \times 1 = -0.588}

The minus sign indicates that the value of h is actually decreasing. The required answer is 0.588.

b. From the diagram, infer that 16 \sin{\theta} = b. When b = 8, then \theta = \arcsin{0.5} = \ang{30}.

Differentiate the above equation w.r.t t

\displaystyle{16 \cos{\theta} \frac{d\theta}{dt} = \frac{db}{dt} \implies \frac{d\theta}{dt} = \frac{1}{16 \cos{\theta}} = \frac{1}{13.856} = \mathbf{0.0722}}

c. The area of the triangle is given by A = 0.5\times h \times b. Differentiating w.r.t t,

\displatstyle{\frac{dA}{dt} = 0.5 b \frac{dh}{dt} + 0.5 h \frac{db}{dt}}

Plugging in b = 8, h = 13.856, \frac{dh}{dt} = -0.588,

\frac{dA}{dt} = -2.352 + 6.928 = \mathbf{4.576 ft^2/sec}

8 0
4 years ago
What is there constant variation of y=kx through (5,8)
swat32

The value of constant of variation "k" is

Solution:

Given that the direct variation is:

y = kx ----- eqn 1

Where "k" is the constant of variation

Given that the point is (5, 8)

To find the value of "k" , substitute (x, y) = (5, 8) in eqn 1

Thus the value of constant of variation "k" is k = 8/5 or 1.6

I hope this is correct and helps!

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3 years ago
A recipe calls for 12 cups of blueberries to make 7 jars of blueberry jam. What is true about the number of cups of blueberries
podryga [215]
The twelve cups have to be divided evenly between the seven jars 
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How many sides does a regular polygon have if each of its interior angle measures 120 degree​
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6 sides .

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What is the value of x?
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I think the answer would be B. 4 cm
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