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3 years ago

8

What's the answer nsbdbbdsbzhbcbxbxbdvchxf

2 answers:

xeze [42]3 years ago

8 0

1. 60 students

2. 38% of students

3. 50 students

4. 18% of students

5. 79200 ft = 15 mi

6. 3600 sec = 1 hr

kifflom [539]3 years ago

7 0

There are 79,200 feet in 15 miles.

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On a coordinate plane, a curved line with a minimum value of (negative 1.25, negative 3.25) and a maximum value of (0.25, negati

soldier1979 [14.2K]

The statement which is true about the end behavior of the graphed function is third option that is as the x-values go to negative infinity, the function's values are equal to zero.

A coordinate plane is a two dimensional plane formed by the intersection of two number lines . One of these number lines is a horizontal number lines called the x-axis and the other number line is a vertical number line called the y-axis.

The exact answer is third option that is as the x-values go to negative infinity, the function's values are equal to zero.

Step by step explanation:

Minimum value (negative 1.25, negative 3.25)

Maximum value of (0.25, negative 1.75)

The x intercepts where the graph crosses the x axis.

Value of x when y=0 crosses x axis at (negative 2.25, 0)

The y intercept are where the graph crosses the y axis.

Value of y when x=0 crosses y axis at (0, negative 2)

The line exits the plane at (negative 2.75, 6) and (1.5, 6).

It can be seen from the coordinates that as the x-values go to negative infinity, the function's values are equal to zero, the coordinates of y approaches zero.

Learn more about coordinates from:

brainly.com/question/17206319

#SPJ10

8 0

2 years ago

my son had his 18 months visit to the doctor last week.the nurse took several measurement while we were there.his length(height)

nikitadnepr [17]

18 months ……33inches, weight 25.5 pounds

When he was born = 9 months…20 inches, weight 8, 4 pounds

Every 9 months his height growth is 33-20 = 13 inches, his weight is 25.5-8.4=17.1 pounds

<span>Pounds. This means, for every 9 months, his growth is 13 inches and his weight is 17.1 pounds. For example we can determine his growth in 3 years.</span>

<span>3 years = 36 months, 36= 9*4, his height will be 4*13 inches= 52 inches, his weight will be 4*17.1 = 68.4 pounds </span>

8 0

3 years ago

Simplify expression: <br><br> 3(4x-5) + 4(2x+6)

SVEN [57.7K]

3(4x-5)+4(2x+6)

Distribute.

12x-15+8x+24

12x+8x= 20x

24-15= 9

20x+9 <---- simplified expression

I hope this helps!
~kaikers

6 0

4 years ago

Read 2 more answers

Can someone help me with this please? I will mark you brainliest

lina2011 [118]

Answer:

On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.vvOn the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.vcOn the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.

Step-by-step explanation:

6 0

3 years ago

Find f f'(x)=1+3sqrt(x) f(4)=25

wlad13 [49]

It appears that you have a derivative and want to integrate...

dy/dx=1+3√x

y(x)=x+(2/3)x^(3/2)+C you are given that f(4)=25 so we can solve for the constant of integration...

y(4)=25=4+16/3+C

21=16/3+C

(63-16)/3=C

47/3=C so

f(x)=x+(2/3)x^(3/2)+47/3

f(x)=(3x+2x^(3/2)+47)/3

6 0

3 years ago