Answer:
<em>The answers are for option (a) 0.2070 (b)0.3798 (c) 0.3938
</em>
Step-by-step explanation:
<em>Given:</em>
<em>Here Section 1 students = 20
</em>
<em>
Section 2 students = 30
</em>
<em>
Here there are 15 graded exam papers.
</em>
<em>
(a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070
</em>
<em>
(b) Here if x is the number of students copies of section 2 out of 15 exam papers.
</em>
<em> here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15
</em>
<em>Then,
</em>
<em>
Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798
</em>
<em>
(c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1)
</em>
<em>
so,
</em>
<em>
Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938
</em>
<em>
Note : Here the given distribution is Hyper-geometric distribution
</em>
<em>
where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>
Answer:
Step-by-step explanation:
roots are (2+3i) and (2-3i)
reqd. eq. is (x-2-3i)(x-2+3i)=0
or (x-2)²-(3i)²=0
or x²-4x+9-9i²=0
or x²-4x+9+9=0
or x²-4x+18=0
X = cost of car before tax
Total cost = (cost of car before tax) + (tax amount)
Total cost = x + 5% of x
Total cost = x + 0.05x
Total cost = 1.05x
The total cost is given to be $14,512, which means
<span>Total cost = 1.05x = 14512
</span>
1.05x = 14512
1.05x/1.05 = 14512/1.05
x = 13,820.95238
x = 13,820.95
The total cost of the car before tax, to the nearest cent, is $13,820.95
1 Substitute
y
=
2
x
−
10
y=2x−10 into
y
=
4
x
−
8
y=4x−8.
2
x
−
10
=
4
x
−
8
2x−10=4x−8
2 Solve for
x
x in
2
x
−
10
=
4
x
−
8
2x−10=4x−8.
x
=
−
1
x=−1
3 Substitute
x
=
−
1
x=−1 into
y
=
2
x
−
10
y=2x−10.
y
=
−
12
y=−12
4 Therefore,
x
=
−
1
y
=
−
12
x=−1
y=−12
The answer is b because its makes sense