Can somebody help me solve this equation?

To biil customers for water usage, one city converts the number of gallons used into units. This relationship is represented by

Finger [1]

The answer to this question would be:
B.) u is the dependent variable.

In this case, the gallon is converted into unit which means the number of gallons is fixed(got from the customer water usage) but the number of units depends on the number of the gallon(748unit for every gallon). That is why "unit" become the dependent variable and "gallon" become the independent variable.

3 0

3 years ago

Read 2 more answers

The abdominopelvic region that is bordered by all four imaginary lines is the

Ainat [17]

Umbilical point.

An umbilic point, likewise called just an umbilic, is a point on a surface at which the arch is the same toward any path.

In the differential geometry of surfaces in three measurements, umbilics or umbilical focuses are focuses on a surface that are locally round. At such focuses the ordinary ebbs and flows every which way are equivalent, consequently, both primary ebbs and flows are equivalent, and each digression vector is a chief heading. The name "umbilic" originates from the Latin umbilicus - navel.

Umbilic focuses for the most part happen as confined focuses in the circular area of the surface; that is, the place the Gaussian ebb and flow is sure. For surfaces with family 0, e.g. an ellipsoid, there must be no less than four umbilics, an outcome of the Poincaré–Hopf hypothesis. An ellipsoid of unrest has just two umbilics.

4 0

3 years ago

Andrew is flying a kite at a height of 120ft. While the wind is carrying the kite horizontally away from her at the rate of 24ft

Paha777 [63]

Answer:

The string of the kite is being let out at the rate of 19.2 ft/sec.

Step-by-step explanation:

See the diagram attached.

The vertical height (BK) of the kite is 120 ft.

The kite string is of length (AK) of 200 ft.

Therefore, the horizontal distance (AB) from Andrew to kite is = $\sqrt{200^{2} - 120^{2}} = 160$ ft.

Now, applying the Pythagoras Theorem,

AB² + BK² = AK²

⇒ l² + h² = s² {Where, l is the horizontal length, h is the height and s is the string length}

Differentiating with respect to time t both sides

$2l\frac{dl}{dt} + 0 = 2s\frac{ds}{dt}$ {Since, height of kite is constant}

⇒ $2 \times 160 \times 24 = 2 \times 200 \times \frac{ds}{dt}$

⇒ $\frac{ds}{dt} = 19.2$ ft per sec.

Therefore, when the wind is carrying the kite horizontally at the rate of 24 ft/sec, then the string of the kite is being let out at the rate of 19.2 ft/sec. (Answer)

3 0

3 years ago

Solve for z. –2.9 + 4.2z = –14.73 − 12.74 + 0.3z z =

Kobotan [32]

Answer:

$\boxed{z = -6.3}$

Step-by-step explanation:

$= > - 2.9 + 4.2z = - 14.73 - 12.74 + 0.3z \\ \\ = > - 2.9 + 4.2z = - 27.47 + 0.3z \\ \\ = > 4.2z - 2.9 = 0.3z - 27.47 \\ \\ = > 4.2z - 0.3z - 2.9 = - 27.47 \\ \\ = > 3.9z = - 27.47 + 2.9 \\ \\ = > 3.9z = - 24.57 \\ \\ = > z = - \frac{24.57}{3.9} \\ \\ = > z = - 6.3$

4 0

3 years ago

Ingrid and Reed want to choose a tool that will allow them to measure the volume of a box. Which tool is most useful for Ingrid

valina [46]

A tape measure will give LxWxH of the box giving you volume

4 0

3 years ago